Percentage of C, H & N of a compound is given as follows:
C=40%, H=13.33%, N=46.67%
The empirical formula of the compound will be:

1. CH2N

2. C2H4N

3. CH4N

4. CH3N

Subtopic:  Empirical & Molecular Formula |
 76%
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AIPMT - 1998
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 The empirical formula of an oxide of iron, which has 69.9% iron and 30.1% oxygen by mass is -

1. FeO

2. Fe2O3

3. Fe3O4

4. Fe3O2

Subtopic:  Empirical & Molecular Formula |
 62%
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 If 2.74 g of the metal oxide contains 1.53 g of metal, then the empirical formula of vanadium oxide is:

(Atomic Mass of V = 52)

1. V2O3

2. VO

3. V2O5

4. V2O7

Subtopic:  Empirical & Molecular Formula |
 59%
From NCERT
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