The mole ratio of H₂ and O₂ gas is 8:1. The ratio of their weight will be:

1. 1 : 1
2. 2 : 1
3. 4 : 1
4. 1 : 2

The specific volume of cylindrical virus particle is $6.02$ $\times$ ${10}^{-2}$ $cc/g\mathrm{m\; w}$hose radius and length are 7 Å & 10Å respectively. If $N_A$ $=$ $6.02$ $\times {10}^{\mathrm{23, }}$find the molecular weight.

1. 15.4 kg/mol

2. $1.54$ $\times$ ${10}^4$ $kg/mol$

3. $3.08$ $\times$ ${10}^4$ $kg/mol$

4. $3.08$ $\times$ ${10}^3$ $kg/mol$

Which among the following has the maximum number of molecules?

1. 7 gm N₂

2. 2 gm H₂

3. 16 gm NO₂

4. 16 gm O₂

The maximum number of molecules is present in: