# Calculate  the mole fraction of the solute in a 1.00 m aqueous solution. 1. 0.177 2. 0.771 3. 0.0534 4. 0.0177

Subtopic:  Concentration Based Problem |
68%
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NEET - 2015
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The number of water molecules is maximum in?

 1 18 molecules of water 2 1.8 g of water 3 18 g of water 4 18 moles of water
Subtopic:  Moles, Atoms & Electrons |
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From NCERT
NEET - 2015
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A mixture of gases contains H2 and O2 gases in the ratio of 1 : 4 (w/w). The molar ratio of the two gases in the mixture will be:

 1 1:4 2 4:1 3 16:1 4 2:1
Subtopic:  Moles, Atoms & Electrons |
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From NCERT
NEET - 2015
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When 22.4 litres of H2(g) is mixed with 11.2 litres of Cl2(g), both at STP, the moles of HCl(g) formed is equal to:

1. 1 mol of HCl(g)
2. 2 mol of HCl(g)
3. 0.5 mol of HCl(g)
4. 1.5 mol of HCl(g)

Subtopic:  Moles, Atoms & Electrons |
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From NCERT
AIPMT - 2014
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1.0 g of magnesium is burnt with 0.56 g O2 in a closed vessel. Which reactant is left in excess and by how much? (At. wt. Mg = 24; O = 16)

 1 Mg, 0.16 g 2 ${O}_{2}$, 0.16 g 3 Mg, 0.44 g 4 ${O}_{2}$, 0.28 g
Subtopic:  Moles, Atoms & Electrons |
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From NCERT
AIPMT - 2014
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The weight of 70 % HNOconcentrated nitric acid solution that should be used to prepare 250 mL of 2.0 M HNO3  is:
1. 90.0 g conc. HNO3
2. 70.0 g conc. HNO3
3. 54.0 g conc. HNO3
4. 45.0 g conc. HNO3
Subtopic:  Concentration Based Problem |
64%
From NCERT
AIPMT - 2013
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6.02 × 1020 molecules of urea are present in 100 mL of its solution. The concentration of the solution is:
1. 0.01 M
2. 0.001 M
3. 0.1 M
4. 0.02 M
Subtopic:  Concentration Based Problem |
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From NCERT
AIPMT - 2013
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Mole fraction of solute in a 1.00 molal aqueous solution is:
1.  0.0177
2.  0.0344
3.  1.770
4.  0.1770

Subtopic:  Concentration Based Problem |
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From NCERT
AIPMT - 2011
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25.3 g of sodium carbonate, Na2CO3, is dissolved in enough water to make 250 mL of a solution. If sodium carbonate completely dissociates, the molar concentrations of sodium ion, Na+ and carbonate ion, $C{O}_{3}^{2-}$are respectively:
(molar mass of Na2CO3 = 106g mol-1)

1. 0.955 M and 1.910 M
2. 1.910 M and 0.955 M
3. 1.90 M and 1.910 M
4. 0.477 M and 0.477 M

Subtopic:  Concentration Based Problem |
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AIPMT - 2010
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The number of atoms in 0.1 mole of a triatomic gas is (NA= 6.02 x 1023 mol-1):

1. $6.026×{10}^{22}$

2. $1.806×{10}^{23}$

3. $3.600×{10}^{23}$

4. $1.800×{10}^{22}$

Subtopic:  Moles, Atoms & Electrons |
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From NCERT
AIPMT - 2010
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