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Q. No.Among the following, choose the ones with equal number of atoms
Choose the correct answer from the options given below:
1. B, C, and D only
2. B, D, and E only
3. A, B, and C only
4. A, ,B and D only
| A. | \(212 ~g ~\text{of}~Na_2CO_3 (s) \text{[molar mass}=106 ~g]\) |
| B. | \(~248 g ~\text{of}~ {Na}_2 \mathrm{O}({s}) [\text{molar mass} =62 \mathrm{~g} ]\) |
| C. | \(240 g ~\text{of} ~NaOH (s)~ [\text{molar mass} =40 \mathrm{~g} \) |
| D. | \( 12 g~ \text{of}~ \mathrm{H}_2(\mathrm{~g})[ \text{molar mass} =2 \mathrm{~g}].\) |
| E. | \( 220 g~ \text{of} ~\mathrm{CO}_2(\mathrm{~g})[\text{ molar mass }=44 \mathrm{~g}]\) |
1. B, C, and D only
2. B, D, and E only
3. A, B, and C only
4. A, ,B and D only
Subtopic: Moles, Atoms & Electrons |
55%
From NCERT
NEET - 2025
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Dalton's Atomic theory could not explain which of the following?
1. Law of multiple proportion
2. Law of gaseous volume
3. Law of conservation of mass
4. Law of constant proportion
1. Law of multiple proportion
2. Law of gaseous volume
3. Law of conservation of mass
4. Law of constant proportion
Subtopic: Introduction |
65%
From NCERT
NEET - 2025
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Which of the following contains the highest number of helium atoms?
1. 4 u of helium
2. 4 g of helium
3. 2.27 L of helium at STP
4. 4 mol of helium
1. 4 u of helium
2. 4 g of helium
3. 2.27 L of helium at STP
4. 4 mol of helium
Subtopic: Moles, Atoms & Electrons |
77%
From NCERT
NEET - 2024
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NEET 2026 - Target Batch - Vital
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NEET 2026 - Target Batch - Vital
1 gram of sodium hydroxide was treated with 25 mL of 0.75 M HCl solution, the mass of sodium hydroxide left unreacted is equal to :
1. 250 mg
2. Zero mg
3. 200 mg
4. 750 mg
1. 250 mg
2. Zero mg
3. 200 mg
4. 750 mg
Subtopic: Millimole/Equivalent Concept |
54%
From NCERT
NEET - 2024
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A compound X contains 32% of A, 20% of B and remaining percentage of C. Then, the empirical formula of X is :
(Given atomic mass of A = 64; B = 40; C = 32u)
1. ABC3
2. AB2C2
3. ABC4
4. A2BC2
(Given atomic mass of A = 64; B = 40; C = 32u)
1. ABC3
2. AB2C2
3. ABC4
4. A2BC2
Subtopic: Empirical & Molecular Formula |
76%
From NCERT
NEET - 2024
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4.74 g of an inorganic compound contains 0.39g of K, 0.27 g of Al, 1.92 g of \(\mathrm{SO_4}\) radicals and 2.16 g of water. If molar mass of the compound is \(948 \mathrm{~g} \mathrm{~mol}^{-1},\) the molecular formula of the inorganic compound is:
| 1. | \(\mathrm{{KAl}({SO}_4)_2 \cdot 12 {H}_2 {O}}\) |
| 2. | \(\mathrm{{K}_2 {Al}_2({SO}_4)_6 \cdot 12 {H}_2 {O}}\) |
| 3. | \(\mathrm{{K}_2 {SO}_4 \cdot {Al}_2({SO}_4)_3 \cdot24 {H}_2 {O}}\) |
| 4. | \(\mathrm{{K}_2 {SO}_6 \cdot {Al}_2({SO}_4)_3 \cdot12 {H}_2 {O}}\) |
Subtopic: Empirical & Molecular Formula |
59%
From NCERT
NEET - 2024
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Molar mass of a compound \(\text{(X)}\) whose \(2.6 \mathrm{~mol}\) weighs \(312 \mathrm{~g}\) is:
| 1. | \(312 \mathrm{~g} \mathrm{~mol}^{-1}\) | 2. | \(120 \mathrm{~g} \mathrm{~mol}^{-1}\) |
| 3. | \(60 \mathrm{~g} \mathrm{~mol}^{-1}\) | 4. | \(811.2 \mathrm{~g} \mathrm{~mol}^{-1}\) |
Subtopic: Empirical & Molecular Formula |
85%
From NCERT
NEET - 2024
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How much glucose is needed to prepare 250 mL of a 1/20 M (M/20) glucose solution?
(Molar mass of glucose: 180 g/mol)
1. 2.25 g
2. 4.5 g
3. 0.44 g
4. 1.125 g
(Molar mass of glucose: 180 g/mol)
1. 2.25 g
2. 4.5 g
3. 0.44 g
4. 1.125 g
Subtopic: Concentration Based Problem |
81%
From NCERT
NEET - 2024
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1.0 g of \(H_2\) has same number of molecules as in:
| 1. | 14 g of \(N_2\) | 2. | 18 g of \(H_2O\) |
| 3. | 16 g of CO | 4. | 28 g of \(N_2\) |
Subtopic: Moles, Atoms & Electrons |
81%
From NCERT
NEET - 2024
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The mass of CO2 produced by heating 20 g of 20% pure limestone as per the equation given below is:
\(\mathrm{CaCO}_3(\mathrm{~s}) \xrightarrow{\text { heat }} \mathrm{CaO}(s)+\mathrm{CO}_2(\mathrm{~g})\)
\(\mathrm{CaCO}_3(\mathrm{~s}) \xrightarrow{\text { heat }} \mathrm{CaO}(s)+\mathrm{CO}_2(\mathrm{~g})\)
| 1. | 1.32 g | 2. | 1.12 g |
| 3. | 1.76 g | 4. | 2.64 g |
Subtopic: Equation Based Problem |
75%
From NCERT
NEET - 2023
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