The value of Henry's constant K-

1. Increases with increase in temperature.

2. Decreases with increase in temperature.

3. Remains constant.

4. First increases then decreases.

Subtopic:  Concentration Terms & Henry's Law |
63%
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The mole fraction of ethylene glycol (C2H6O2) in a solution containing 20% of C2H6O2 by mass is-

1. 0.932

2. 0.0672

3. 0.832

4. 0.732

Subtopic:  Concentration Terms & Henry's Law |
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If N2 gas is bubbled through water at 293 K, how many millimoles of N2 gas would dissolve in 1 litre of water?
(
Partial pressure of nitrogen = 0.987 bar, Henry’s law constant for N2 at 293 K = 76.48 kbar).

1. 0.716 mmol

2. 0.616 mmol

3. 0.726 mmol

4. 0.516 mmol

Subtopic:  Concentration Terms & Henry's Law |
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The mixture that shows positive deviation from Raoult's law is-

1. Benzene + Toluene

2. Acetone + Chloroform

3. Chloroethane + Bromoethane

4. Ethanol + Acetone

Subtopic:  Raoult's Law |
67%
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NEET - 2020
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The correct option for the value of vapour pressure of a solution at 45 $°$C with benzene to octane in a molar ratio 3:2 is:

[At 45 $°$C vapour pressure of benzene is 280 mm Hg and that of octane is 420 mm Hg. Assume Ideal gas]
1. 336 mm of Hg
2. 350 mm of Hg
3. 160 mm of Hg
4. 168 mm of Hg

Subtopic:  Raoult's Law |
72%
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NEET - 2021
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Vapour pressure of chloroform (CHCl3) and dichloromethane (CH2Cl2at 298 K are 200 mm Hg and 415 mm Hg respectively. The vapour pressure of the solution prepared by mixing 25.5 g of CHCl3 and 40 g of CH2Cl2 at 298 K is 347.9 mm Hg.

The mole fractions of each component, that is, CHCl
3 and CH2Cl2 in vapour phase are respectively-

0.82; 0.18
2. 0.16; 0.84
3. 0.18; 0.82
4. 0.84; 0.16

Subtopic:  Raoult's Law |
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The partial pressure of ethane over a saturated solution containing 6.56 X 10-2 g of ethane is 1 bar. If the solution contains 5.00 X 10-2 g of ethane, then what shall be the partial pressure of the gas?

1. 0.76 bar

2. 0.16 bar

3. 1.16 bar

4. 3.12 bar

Subtopic:  Concentration Terms & Henry's Law |
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On mixing, heptane, and octane form an ideal solution at 373 K, the vapor pressures of the two liquid components (Heptane and octane) are 105 kPa and 45 kPa respectively. Vapour pressure of the solution obtained by mixing 25.0 g of heptane and 35 g of octane will be:
(molar mass of heptane = 100 g mol−1 and of octane =114 g 1 mol−1)

1. 144.5 kPa

2. 72.0 kPa

3. 36.1 kPa

4. 96.2 kPa

Subtopic:  Raoult's Law |
75%
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At 100 °C the vapour pressure of a solution of 6.5 g of a solute in 100 g water is 732 mm. If Kb = 0.52, the boiling point of this solution will be:
1. 100 oC
2. 102 oC
3. 103 oC
4. 101 oC
Subtopic:  Relative Lowering of Vapour Pressure | Elevation of Boiling Point |
59%
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NEET - 2016
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If 8 g of a non-electrolyte solute is dissolved in 114 g of n-octane to reduce its vapor pressure to 80 %, the molar mass (in g mol–1) of the solute is -

[Molar mass of n-octane is 114 g mol–1]

 1 40 2 60 3 80 4 20
Subtopic:  Relative Lowering of Vapour Pressure |
60%
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NEET - 2020
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