At 100 °C the vapour pressure of a solution of 6.5 g of a solute in 100 g water is 732 mm. If Kb = 0.52, the boiling point of this solution will be:
1. 100 oC
2. 102 oC
3. 103 oC
4. 101 oC
Subtopic:  Relative Lowering of Vapour Pressure | Elevation of Boiling Point |
 59%
From NCERT
NEET - 2016
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NEET 2023 - Target Batch - Aryan Raj Singh
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The boiling point of 0.2 mol kg-1 solution of X in water is greater than the equimolal solution of Y in water. The correct statement in this case is:

1. X is undergoing dissociation in water.
2. Molecular mass of X is greater than the molecular mass of Y.
3. Molecular mass of X is less than the molecular mass of Y.
4. Y is undergoing dissociation in water while X undergoes no change.
Subtopic:  Elevation of Boiling Point |
 59%
From NCERT
NEET - 2015
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NEET 2023 - Target Batch - Aryan Raj Singh
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1.00 g of non-electrolyte solute (molar mass 250 g mol-1) was dissolved in 51.2 g of benzene. If the freezing point depression constant, Kf of benzene is 5.12 mol-1 kg K, the freezing point of benzene will be lowered by:

1. 0.4 K

2. 0.3 K

3. 0.5 K

4. 0.2 K

Subtopic:  Elevation of Boiling Point |
 84%
From NCERT
AIPMT - 2006
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NEET 2023 - Target Batch - Aryan Raj Singh
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A solution of urea (molar mass 56 g mol–1) boils at 100.18 ºC at atmospheric pressure. If Kf and Kb for water are 1.86 and 0.512 K kg mol–1 respectively, the above solution will freeze at:

1. –6.54 ºC

2. –0.654 ºC

3. 6.54 ºC

4. 0.654 ºC

Subtopic:  Elevation of Boiling Point | Depression of Freezing Point |
 75%
From NCERT
AIPMT - 2005
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NEET 2023 - Target Batch - Aryan Raj Singh
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NEET 2023 - Target Batch - Aryan Raj Singh