- 1(current)
Q. No.One mole of sugar is dissolved in three moles of water at 298 K. The relative lowering of vapour pressure is:
| 1. | 0.25 | 2. | 0.15 |
| 3. | 0.50 | 4. | 0.33 |
If 8 g of a non-electrolyte solute is dissolved in 114 g of n-octane to reduce its vapor pressure to 80 %, the molar mass (in g mol–1) of the solute is -
[Molar mass of n-octane is 114 g mol–1]
| 1. | 40 | 2. | 60 |
| 3. | 80 | 4. | 20 |
The largest freezing point depression among the following O.10 m solutions is shown by:
| 1. | \(\mathrm{KCl}\) | 2. | \(\mathrm{C_6H_{12}O_6}\) |
| 3. | \(\mathrm{Al}_2(\mathrm{SO_4})_3\) | 4. | \(\mathrm{K_2SO_4}\) |
An aqueous solution is 1.00 molal in KI. The vapour pressure of the solution can be increased by:
1. Addition of NaCl
2. Addition of Na2SO4
3. Addition of 1.00 molal Kl
4. Addition of water
The vapour pressure of a solvent decreased by 10 mm of Hg when a non-volatile solute was added to the solvent. The mole fraction of the solute in solution is 0.2. What would be the mole fraction of the solvent if the decrease in vapour pressure is 20 mm of Hg:
1. 0.2
2. 0.4
3. 0.6
4 0.8
- 1(current)
Q. No.
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