During osmosis, the flow of water through a semi-permeable membrane is:

1. From a solution having higher concentration only. 
2. From both sides of the semi-permeable membrane with equal flow rates.
3. From both sides of the semi-permeable membrane with unequal flow rates.
4. From a solution having lower concentration only.

Subtopic:  Osmosis & Osmotic Pressure |
From NCERT
AIPMT - 2006
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For an ideal solution, the correct option is -

1. mix G=0 at constant T and P

2. mix S=0 at constant T and P

3. mix V0 at constant T and P

4. mix H=0 at constant T and P

Subtopic:  Raoult's Law |
 79%
From NCERT
NEET - 2019
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The mixture among the following that forms maximum boiling azeotrope is:

1. Heptane + Octane
2. Water + Nitric acid
3. Ethanol + Water
4. Acetone + Carbon disulphide

Subtopic:  Azeotrope |
 68%
From NCERT
NEET - 2019
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A solution of acetone in ethanol:

1. Shows a negative deviation from Raoult's law

2. Shows a positive deviation from Raoult's law

3. Behaves like a near-ideal solution

4. Obeys Raoult's law

Subtopic:  Raoult's Law |
 76%
From NCERT
AIPMT - 2006
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1.00 g of non-electrolyte solute (molar mass 250 g mol-1) was dissolved in 51.2 g of benzene. If the freezing point depression constant, Kf of benzene is 5.12 mol-1 kg K, the freezing point of benzene will be lowered by:

1. 0.4 K

2. 0.3 K

3. 0.5 K

4. 0.2 K

Subtopic:  Elevation of Boiling Point |
 84%
From NCERT
AIPMT - 2006
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A solution containing 10 g/dm3 of urea (molecular mass = 60 g mol-1) is isotonic with a 5 % solution of a non-volatile solute. The molecular mass of this non-volatile solute is:

1. 25 g mol-1 2. 300 g mol-1
3. 350 g mol-1 4. 200 g mol-1
Subtopic:  Introduction & Colligative properties |
 82%
From NCERT
AIPMT - 2006
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0.5 molal aqueous solution of a weak acid (HX) is 20 % ionised. The lowering in the freezing point of the solution will be:
[Kf for water = 1.86 K kg mol-1]

1. -1.12 K

2. 0.56 K

3. 1.12 K

4. -0.56 K

Subtopic:  Depression of Freezing Point | Van’t Hoff Factor |
 54%
From NCERT
AIPMT - 2007
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A 0.0020 m aqueous solution of an ionic compound Co(NH3)5(NO2)Cl freezes at -0.0073 oC. The number of moles of ions that 1 mol of ionic compound produces on being dissolved in water will be:
(Kf = -1.86 oC/m)

1. 2 2. 3
3. 4 4. 1
Subtopic:  Depression of Freezing Point | Van’t Hoff Factor |
 66%
From NCERT
AIPMT - 2009
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A solution of sucrose (molar mass = 342 g mol–1) has been prepared by dissolving 68.5 g of sucrose in 1000 g of water. The freezing point of the solution obtained will be: 
(kf for water = 1.86 K kg mol–1)
1. –0.372 oC
2. –0.520 oC
3. +0.372 oC
4. –0.570 oC

Subtopic:  Depression of Freezing Point |
 81%
From NCERT
AIPMT - 2010
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An aqueous solution is 1.00 molal in KI. The vapour pressure of the solution can be increased by:

1. Addition of NaCl

2. Addition of Na2SO4

3. Addition of 1.00 molal Kl

4. Addition of water

Subtopic:  Relative Lowering of Vapour Pressure |
 62%
From NCERT
AIPMT - 2010
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