The incorrect statement among the following for an ideal solution is:

1. \(\Delta H_{\text{Mix}}=0\)
2. \(\Delta U_{\text{Mix}}=0\)
3. \(\Delta P=P_{\text{obs.}}-P_{\text{(Calculated by Raoult's law)}}=0\)
4. \(\Delta G_{\text{Mix}}=0\)

Subtopic:  Raoult's Law |
 81%
From NCERT
NEET - 2016
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NEET 2023 - Target Batch - Aryan Raj Singh
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At 100 °C the vapour pressure of a solution of 6.5 g of a solute in 100 g water is 732 mm. If Kb = 0.52, the boiling point of this solution will be:
1. 100 oC
2. 102 oC
3. 103 oC
4. 101 oC
Subtopic:  Relative Lowering of Vapour Pressure | Elevation of Boiling Point |
 59%
From NCERT
NEET - 2016
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Consider the following statements about the composition of the vapour over an ideal 1:1 molar mixture of benzene and toluene. The correct statement is:

Assume that the temperature is constant at 25 oC.
(Given, vapour pressure data at 25 °C, benzene = 12.8 kPa, toluene = 3.85 kPa)

1. The vapour will contain a higher percentage of toluene.
2. The vapour will contain equal amounts of benzene and toluene.
3. Not enough information is given to make a prediction.
4. The vapour will contain a higher percentage of benzene.
Subtopic:  Introduction & Colligative properties |
 63%
From NCERT
NEET - 2016
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For an ideal solution, the non-zero value will be for:

1. \(\Delta H_\text{mix}\)
2. \(\Delta S_\text{mix}\)
3. \(\Delta V_\text{mix}\)
4. \(\Delta P=P_{\text{observed}}-P_{\text{Raoult}}\)
Subtopic:  Introduction & Colligative properties |
 84%
From NCERT
NEET - 2015
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The boiling point of 0.2 mol kg–1 solution of X in water is greater than the equimolal solution of Y in water. The correct statement in this case is:

1. X is undergoing dissociation in water.
2. Molecular mass of X is greater than the molecular mass of Y.
3. Molecular mass of X is less than the molecular mass of Y.
4. Y is undergoing dissociation in water while X undergoes no change.
Subtopic:  Elevation of Boiling Point |
 59%
From NCERT
NEET - 2015
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The electrolyte having the same value of Van't Hoff factor (i) as that of Al2(SO4)3  (if all are 100% ionized) is:

1. K2SO4
2. K3[Fe(CN)6]
3. Al(NO3)3
4. K4[Fe(CN)6]

Subtopic:  Introduction & Colligative properties | Van’t Hoff Factor |
 85%
From NCERT
NEET - 2015
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The largest freezing point depression among the following 0.10 m solutions is shown by:

1. \(\mathrm{KCl}\) 2. \(\mathrm{C_6H_{12}O_6}\)
3. \(\mathrm{Al}_2(\mathrm{SO_4})_3\) 4. \(\mathrm{K_2SO_4}\)
Subtopic:  Relative Lowering of Vapour Pressure |
 80%
From NCERT
AIPMT - 2014
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pA and pB are the vapour pressure of pure liquid components, A and B, respectively of an ideal binary solution.
If XA represents the mole fraction of component A, the total pressure of the solution will be:

1. pA + XA (pB-pA)
2. pA + X(pA-pB)
3. pB + X(pB-pA)
4. pB + X(pA-pB)

Subtopic:  Dalton’s Law of Partial Pressure |
 70%
From NCERT
AIPMT - 2012
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The freezing point depression constant for water is 1.86 oC m-1. If 5.00 g Na2SOis dissolved in 45.0 g H2O, the freezing point is changed by -3.82 oC. The van’t Hoff factor for Na2SO4 is:

1. 2.63 2. 3.11
3. 0.381 4. 2.05
Subtopic:  Depression of Freezing Point |
 69%
From NCERT
AIPMT - 2011
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NEET 2023 - Target Batch - Aryan Raj Singh
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The van’t Hoff factor, i, for a compound that undergoes
dissociation and association in a solvent is, respectively:

1. Less than one and less than one.
2. Greater than one and less than one.
3. Greater than one and greater than one.
4. Less than one and greater than one.

Subtopic:  Van’t Hoff Factor |
 85%
From NCERT
AIPMT - 2011
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