The following solutions were prepared by dissolving 10 g of glucose (C₆H₁₂O₆)
in 250 ml of water (P₁), 10 g of urea (CH₄N₂O) in 250 ml of water (P₂) and 10 g
of sucrose (C₁₂H₂₂O₁₁) in 250 ml of water (P₃). The decreasing order of osmotic
the pressure of these solutions is:

1.	P2 > P3 > P1	2.	P3 > P1 > P2
3.	P2 > P1 > P3	4.	P1 > P2 > P3

The correct option for the value of vapor pressure of a solution at 45 $°$C with benzene to octane in a molar ratio 3:2 is:

[At 45 $°$C vapor pressure of benzene is 280 mm Hg and that of octane is 420 mm Hg. Assume Ideal gas]
1. 336 mm of Hg
2. 350 mm of Hg
3. 160 mm of Hg
4. 168 mm of Hg

Beans get cooked earlier in a pressure cooker, because:

The ideal solution indicates:

A solution contains a non-volatile solute of molecular mass M₂. The molecular mass of solute in terms of osmotic pressure is:
where:

m₂ → Mass of solute

V → Volume of solution

\(\pi\) → Osmotic pressure

1. ${\mathrm{M}}_2=\left(\frac{{\mathrm{m}}_2}{\mathrm{\pi }}\right)\mathrm{VRT}$

2. ${\mathrm{M}}_2=\left(\frac{{\mathrm{m}}_2}{\mathrm{V}}\right)\frac{\mathrm{RT}}{\mathrm{\pi }}$

3. ${\mathrm{M}}_2=\left(\frac{{\mathrm{m}}_2}{\mathrm{V}}\right)\mathrm{\pi RT}$

4. ${\mathrm{M}}_2=\left(\frac{{\mathrm{m}}_2}{\mathrm{V}}\right)\frac{\mathrm{\pi }}{\mathrm{RT}}$

From the colligative properties of a solution, which one is the best method for the determination of molecular weight of proteins & polymers:

1. Osmotic pressure

2. Lowering of vapour pressure 

3. Lowering of freezing point

4. Elevation in boiling point

The vapour pressure of a solvent decreased by 10 mm of Hg when a non-volatile solute was added to the solvent. The mole fraction of the solute in solution is 0.2. What would be the mole fraction of the solvent if the decrease in vapour pressure is 20 mm of Hg:
1. 0.2
2. 0.4
3. 0.6
4  0.8

1 % (w/w) solution of a compound is isotonic with 5 % (w/w) sucrose (sugar) solution. The molecular weight of the compound will be:

The addition of water vapour does not change the density of:

1. CCl₄

2. CS₂

3. Ether

4. Coke

A solution has a 1:4 mole ratio of pentane to hexane.
The vapor pressures of the pure hydrocarbons at 20 ºC are
440 mm Hg for pentane and 120 mm Hg for hexane.
The mole fraction of pentane in the vapor phase would be: