MnO42- undergoes disproportionation reaction in acidic medium but MnO4- does not. It is:

1.  Due to the highest oxidation state of Mn in  MnO42-
2.  Due to the highest oxidation state of Mn in  MnO4-
3.  Due to the endothermic nature of the disproportionation reaction.
4.  Due to the exothermic nature of the disproportionation reaction.

Subtopic:  Introduction to Redox and Oxidation Number |
 81%
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Nitric acid reacts with PbO but does not react with PbO, because -

1. PbO is a base while PbO2 is a strong oxidizing reagent

2. PbO is a base while PbO2 is a weak oxidizing reagent

3. PbO is neutral while PbO2 is a strong oxidizing reagent

4. PbO is acid while PbO2 is a strong oxidizing reagent

Subtopic:  Oxidizing & Reducing Agents |
 60%
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The oxidation state of P in HPO32- is-

1. +3 2. +4
3. +2 4. +5
Subtopic:  Introduction to Redox and Oxidation Number |
 84%
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The oxidation state of two S-atoms in Na2S2O3 is -

1. +2 and +4

2. +3 and -2

3. +4 and -2

4. +6 and -2

Subtopic:  Introduction to Redox and Oxidation Number |
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(a) \(E_{k^+/K}^o = - 2.93\ V\); \(E_{Ag^+/Ag}^o = 0.80\ V\)
(b) \(E_{Hg^{2+}/Hg}^o = 0.79\ V\); \(E_{Mg^{2+}/Mg}^o = - 2.37\ V\)  
(c) \(E_{Cr^{3+}/Cr}^o = -0.74\ V\)

Based on standard electrode potentials given above, the correct arrangement for increasing order of reducing power of
elements is: 

1. \(\mathrm{Ag}<\mathrm{Hg}<\mathrm{Cr}<\mathrm{Mg}<\mathrm{K} \)
2. \(\mathrm{Ag}>\mathrm{Cr}>\mathrm{Mg}>\mathrm{Hg}>\mathrm{K}\)
3. \(\mathrm{K}>\mathrm{Mg}<\mathrm{Cr}<\mathrm{Hg}>\mathrm{Ag} \)
4. \(\mathrm{K}<\mathrm{Mg}<\mathrm{Cr}<\mathrm{Hg}<\mathrm{Ag}\)
Subtopic:  Emf & Electrode Potential |
 74%
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In the given reaction, what is the name of the species that bleaches the substances due to its oxidising action?

Cl2(g) + 2OH-(aq) → ClO-(aq) + Cl-(aq) + H2O(l)

1. ClO- 

2. Cl2

3. Cl-

4. Both ClO- and Cl-

Subtopic:  Oxidizing & Reducing Agents |
 50%
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The oxidation number of the atom (in bold) in the following species is given. Identify, which one is incorrectly related?

1. \(\mathbf{Cu}_{2} O\) is \(- 1\)

2. \(\mathbf{Cl} O_{3}^{-}\) is \(+ 5\)

3. \(K_{2} \mathbf{Cr}_{2} O_{7}\) is \(+ 6\)

4. \(H \mathbf{Au} Cl_{4}\) is \(+ 3\)

Subtopic:  Oxidizing & Reducing Agents |
 83%
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The element that does not show a disproportionation tendency is/are:

1. Cl

2. Br

3. F

4. I

Subtopic:  Oxidizing & Reducing Agents |
 83%
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Assertion (A): In the presentation 
\( \mathrm{E}_{\mathrm{Fe}^{3+}}^{\ominus} /_{ \mathrm{Fe}^{2+}}\) \( \text { and } \mathrm{E}_{\mathrm{Cu}^{2+}}^{\ominus} / _{\mathrm{Cu}^{\prime}} \mathrm{Fe}^{3+} / \mathrm{Fe}^{2+} \) and\(\text { } \mathrm{Cu}^{2+} / \mathrm{Cu}\) are reodox couples
Reason (R): A redox couple is the combination of the oxidised and reduced forms of a substance involved in an oxidation or reduction half cell.
 
1. Both (A) and (R) are True and (R) is the correct explanation of (A).
2. Both (A) and (R) are True but (R) is not the correct explanation of (A).
3. (A) is True but (R) is False.
4. (A) is False but (R) is True.
Subtopic:  Introduction to Redox and Oxidation Number |
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Given below are two statements: 

Assertion (A): The decomposition of hydrogen peroxide to form water and oxygen is an example of a disproportionation reaction.
Reason (R): The oxygen of peroxide is in –1 oxidation state and it is converted to zero oxidation state in O2
and –2 oxidation state in H2O.

1. Both (A) and (R) are true and (R) is the correct explanation of (A).
2. Both (A) and (R) are true but (R) is not the correct explanation of (A).
3. (A) is true but (R) is false.
4. (A) is false but (R) is true.

Subtopic:  Redox Titration & Type of Redox |
 89%
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