Consider the following equation:

Cr₂O₇^2–_(aq) + 3SO₃^2– _(aq)+ 8H⁺_(aq) →  A + B +4H₂O_(l)

The product A and B are respectively-

1. 2Cr²⁺; 3SO₂

2. 2Cr⁺; S₂O₇ ^2-

3. 2Cr³⁺; 3SO₄ ^2-

4. 2Cr³⁺; 3HSO₄^2-

 

aMnO₄^–(aq) + bBr^–(aq) + cH₂O(l) → dMnO₂(s) + eBrO₃^– (aq) + fOH^–(aq)

The value of c, d and f  in the above mentioned reaction are respectively-

1. c=1; d=2; f=2
2. c=2; d=1; f=2
3. c=2; d=2; f=1
d. c=1; d=1; f=1
 

Permanganate(VII) ion, MnO₄^– in basic solution oxidizes iodide ion, I^– to produce molecular iodine (I₂) and manganese (IV) oxide (MnO₂). The reaction is as follows:

aI^–(aq) + bMnO₄^–(aq) + cH₂O(l) → dI₂(s) + eMnO₂(s) + fOH^–(aq)

The value of b, d and f are-

1. b=2; d=3; f=8
2. b=1; d=3; f=8
3. b=3; d=8; f=2
4. b=8; d=3; f=2