The ionization constant of phenol is 1.0 × 10^–10. The concentration of phenolate ion in 0.05 M solution of phenol will be -

1. 4.2 x 10^-4 M

2. 3.6 x 10^-5 M

3. 7.8 x 10^-6 M

4. 2.2 x 10^-6 M

The first ionization constant of H₂S is 9.1 × 10^–8. The concentration of HS^– ion in its 0.1 M solution will be:

The ionization constant of acetic acid is 1.74 × 10^–5. The pH of acetic acid in its 0.05 M solution will be:

(a) Human muscle-fluid,  pH =6.83 

(b) Human stomach fluid, pH = 1.2

(c) Human blood, pH= 7.38           

(d) Human saliva, pH =6.4.

Out of the above mentioned biological fluids, the one with the minimum concentration of hydrogen ions is:

The pH values of milk, tomato juice, lemon juice, and egg are 6.8, 4.2, 2.2, and 7.8 respectively.

The corresponding hydrogen ion concentration is maximum in: 

The ionization constant of propanoic acid is 1.32 × 10^–5. The degree of ionization of 0.05M acid solution will be:

1. $\mathrm{\alpha }$ = 0.63 x 10^-2

2. $\mathrm{\alpha }$ = 1.63 x 10^-4

3. $\mathrm{\alpha }$ = 1.63 x 10^-2

4. $\mathrm{\alpha }$ = 0.05 x 10^-2

The salt that gives a neutral solution in water is: 

1. KBr

2. NH₄NO₃

3. NaCN

4. Rb₂(CO₃)

The ionization constant of benzoic acid is 6.46×10^–5 and K_sp for silver benzoate is 2.5×10^–13. Silver benzoate is x times more soluble in a buffer of pH 3.19 compared to its solubility in pure water. The value of x will be:

1. 6.8 

2. 16.8 

3. 33.3 

4.  3.3 

${{\mathrm{I}}_2}_{\left(\mathrm{s}\right)}$ $+$ $5{{\mathrm{F}}_2}_{\left(\mathrm{g}\right)}$ $$ $\to 2{\mathrm{IF}}_{5\left(g\right)}$ $$

The equilibrium constant K_c expression for the above mentioned reaction is:

$1.$ ${\mathrm{K}}_{\mathrm{C}}=$ $\frac{{\left[{\mathrm{IF}}_5\right]}^2}{{\left[{\mathrm{F}}_2\right]}^5}$
$2.$ ${\mathrm{K}}_{\mathrm{C}}=$ $\frac{{\left[{\mathrm{IF}}_5\right]}^2}{{\left[{\mathrm{F}}_2\right]}^5\left[{\mathrm{I}}_2\right]}$
$3.$ ${\mathrm{K}}_{\mathrm{C}}$ $=\frac{{\left[{\mathrm{F}}_2\right]}^5\left[{\mathrm{I}}_2\right]}{{\left[{\mathrm{IF}}_2\right]}^2}$
$4.$ $$ ${\mathrm{K}}_{\mathrm{C}}$ $=\frac{{\left[{\mathrm{F}}_2\right]}^5}{{\left[{\mathrm{IF}}_5\right]}^2}$

The solution that has the lowest pH is: 

(assuming 100% dissociation)