The volume of the container containing a liquid and its vapours at a constant temperature is suddenly increased. What would be the effect of the change on vapour pressure?

1. It would decrease initially 2. It would increase initially
3. It would remain the same 4. None of the above

Subtopic:  Introduction To Equilibrium |
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For the following reaction, 

2SO2(g) + O2(g) ⇋ 2SO3(g)

The value of Kc at equilibrium with a concentration of [SO2]= 0.60M,[O2] = 0.82M and [SO3] = 1.90M

would be:

1. 8.5 2. 9.4
3. 12.2 4. 16.3
Subtopic:  Kp, Kc & Factors Affecting them |
 79%
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Pure liquids and solids are ignored while writing the expression for the equilibrium constant because :

1. Size and shape of a pure substance are always fixed. 2. Volume of solids and liquids is relatively fixed.
3. Charges and masses of pure substances are always fixed 4. All of the above
Subtopic:  Kp, Kc & Factors Affecting them |
 51%
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Given the reaction,
\(2 \mathrm{~N}_{2(\mathrm{~g})}+\mathrm{O}_{2(\mathrm{~g})} \leftrightharpoons 2 \mathrm{~N}_2 \mathrm{O}_{(\mathrm{g})}\)

If a mixture of 0.482 mol N2 and 0.933 mol of O2 is placed in a 10 L vessel and allowed to form N2O (Kc= 2.0 × 10–37 L mol-1), the concentration of N2O at equilibrium will be -

1. \(6.6 \times 10^{-21} \mathrm{M} \) 2. \(0.6 \times 10^{-21} \mathrm{M} \)
3. \(4.6 \times 10^{-11} \mathrm{M} \) 4. \(3.6 \times 10^{-31} \mathrm{M}\)
Subtopic:  Kp, Kc & Factors Affecting them |
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For a reaction, 2NO (g) + Br2 (g)  2NOBr (g)

When 0.087 mol of NO and 0.0437 mol of Br2 are mixed in a closed container at a constant temperature, 0.0518 mol of NOBr is obtained at equilibrium. The concentration of NO and Br2 at equilibrium will be:

1. NO = 0.0352 mol; Br2= 0.0178 mol

2. NO = 0.352 mol; Br2= 0.178 mol

3. NO = 0.0634 mol; Br2= 0.0596 mol

4. NO = 0.634 mol; Br2= 0.596 mol

Subtopic:  Introduction To Equilibrium |
 69%
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For the reaction: H2 (g) + I2 (g)  ⇌ 2HI (g) ; Kc54.8 at 700K .

If 0.5 mol L–1 of HI(g) is present at equilibrium at 700 K, the concentration of H2(g) and I2(g)  would be:

1. [H2]= [I2]=0.05 mol L-1

2. [H2]= 0.5 mol L-1, [I2] = 0.05 mol L-1

3. [H2] = 0.068 mol L-1, [I2]= 0.55 mol L-1

4. [H2] = [I2] =0.068 mol L-1

Subtopic:  Kp, Kc & Factors Affecting them |
 63%
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When the initial concentration of ICl is 0.78 M, the equilibrium concentration of ICl will be: 

2ICl(g) ⇋ I2(g) + Cl2(g); Kc = 0.14

1. 0.446 M 2. 0.876 M
3. 0.345 M 4. 0.986 M
Subtopic:  Kp, Kc & Factors Affecting them |
 52%
From NCERT
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Given the reaction:
CH
3COOH(l) + C2H5OH(l)  CH3COOC2H5(l) + H2O(l)

At 293 K, if one starts with 1.00 mol of acetic acid and 0.18 mol of ethanol, there is 0.171 mol of ethyl acetate in the final equilibrium mixture. The equilibrium constant of the reaction will be-

1. 0.78

2. 1.3

3. 2.47

4. 3.92

Subtopic:  Kp, Kc & Factors Affecting them |
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(a) PCl5 (g) PCl3 (g) + Cl2 (g)

(b) CaO (s) + CO2 (g)   CaCO3 (s)

(c) 3Fe (s) + 4H2O (g)  Fe3O4 (s) + 4H2 (g)

The effect of an increase in the volume on the number of moles of products in the above-mentioned reactions would be, respectively:

1. a) Increase,  b) decrease, c) same

2. a) Decrease,  b) same, c) increase

3. a) Increase,  b) increase, c) same

4. a) Increase,  b) decrease, c) increase

Subtopic:  Le Chatelier's principle |
 70%
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Consider the following reactions.

(i) COCl2 (g)  ⇋ CO (g) + Cl2 (g)

(ii) CO2 (g) + C (s)  2CO (g)

(iii) 2H2 (g) + CO (g)  CH3OH (g)

Which reaction(s) will shift in a backward manner when the pressure is increased?

1. Only (iii)

2. Only (ii)

3. Both (i) and (ii) 

4. None of the above

Subtopic:  Le Chatelier's principle |
 72%
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