The crystal field splitting energy is:

1. The heat of formation between the two levels (eg and t2g)
2. The combined pairing energy of the two levels (eg and t2g)
3. The combined energy of the three levels in octahedral 
4. The combined energy of the two levels (eg and t2g

Subtopic:  VBT, CFT & their Limitations |
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[Cr(NH3)6]3+ is paramagnetic ,while Ni(CN)42- is diamagnetic because:

1. Electrons in the 3d orbitals remain unpaired in Ni(CN)42-
2. Electrons in the 3d orbitals remain unpaired in [Cr(NH3)6]3+
3. Electrons in the 3p orbitals remain unpaired in [Cr(NH3)6]3+
4. Electrons in the 3p orbitals remain unpaired in Ni(CN)42-

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A solution of [Ni(H2O)6]2+ is green, but a solution of [Ni(CN)4]2– is colorless because:

1. There are paired electrons in [Ni(H2O)6]2+ while all electrons are unpaired in [Ni(CN)4]2–
2. There are unpaired electrons in [Ni(H2O)6]2+ while all electrons are paired in [Ni(CN)4]2–
3. There are unpaired electrons in [Ni(H2O)6]2+ and [Ni(CN)4]2–
4. None of the above.

Subtopic:  Introduction, Classification and Nomenclature |
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[Fe(CN)6]4– and [Fe(H2O)6]2+ are of different colors in dilute solutions because :

1. Higher lattice energy value of [Fe(CN)6]4– as compared to [Fe(H2O)6]2+
2. Higher CFSE value of [Fe(CN)6]4– as compared to [Fe(H2O)6]2+
3. Lower CFSE value of [Fe(CN)6]4– as compared to [Fe(H2O)6]2+
4. Lower lattice energy value of [Fe(CN)6]4– as compared to [Fe(H2O)6]2+

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The nature of bonding in metal carbonyls is -

1. The metal-carbon bonds in metal carbonyls have both σ and π characters.
2. The metal-carbon bonds in metal carbonyls have only σ character.
3. The metal-carbon bonds in metal carbonyls have only π character.
4. The metal-carbon bonds in metal carbonyls have only hydrogen bonding.


 

Subtopic:  Organometallic Complexes & their Uses |
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The greater value of the stability constant of complex salt indicates   -

1. The greater proportion of products.

2. The greater proportion of reactants

3. Lesser concentration of catalyst at equilibrium

4 . All of the above

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The correct order for the wavelengths of absorption in the visible region for the following is:





\(\left[\mathrm{Ni}\left(\mathrm{NO}_2\right)_6\right]^{4-},\left[\mathrm{Ni}\left(\mathrm{NH}_3\right)_6\right]^{2+},\left[\mathrm{Ni}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{2+}\)
1. [Ni(H2O)6]2+ < [Ni(NH3)6]2+ < [Ni(NO2)6]4-

2. [Ni(H2O)6]2+ > [Ni(NH3)6]2+ > [Ni(NO2)6]4-

3. [Ni(NH3)6]2+ > [Ni(H2O)6]2+ [Ni(NO2)6]4-

4.  [Ni(H2O)6]2+ [Ni(NO2)6]4- [Ni(NH3)6]2+

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The number of unpaired electrons in the following complexes respectively are-

K4[Mn(CN)6], Fe(H2O)6]2+, K2[MnCl4]

1. 1, 4, 5

2. 2, 4, 5

3. 0, 3, 4

4. 2, 3, 4

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a. Primary valencies are satisfied by negative ions while secondary valences are satisfied by negative ion only. 
b. A metal ion has a definite number of secondary valences around the central atom. 
c. Primary valences are usually ionizable, while secondary valences are non-ionizable


The correct statements among the above are -

1. a, b

2. a, c

3. b, c

4. a, b, c 

Subtopic:  Werner’s Theory |
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Match the following.

Ligand Name Type of ligand
i. NO2- a. Hexadenate
ii. OH- b. Didentate
iii. C2O42- c. Monodentate
iv. EDTA d. Ambidentate ligand

1. i=d, ii=c, iii=b, iv=a

2. i=c, ii=d, iii=b, iv=a

3. i=c, ii=d, iii=a, iv=b

4. i=a, ii=c, iii=b, iv=d

Subtopic:  Ligands |
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