FeSO4 solution mixed with (NH4)2SO4 solution in 1:1 molar ratio gives the test of Fe2+ ion

but CuSO4 solution mixed with aqueous ammonia in 1:4 molar ratio does not give the test of Cu2+ ion because:

1. The former is an example of a basic compound, while the latter is an amphoteric compound
2. The former is an example of an amphoteric compound, while the latter is a basic compound
3. The former is an example of a double salt, while the latter is a coordination compound
4. The former is an example of a coordination compound, while the latter is a double salt

Subtopic:  Introduction, Classification and Nomenclature |
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The oxidation number and coordination number of Co in [Co(H2O)(CN)(en)2]2+respectively are -     

1.) 3, 6

2.) 3, 2

3.) 2, 2

4.) 1, 3

Subtopic:  Introduction, Classification and Nomenclature |
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Total number of optical isomers [Pt(NH3)(Br)(Cl)(py)] can show:

1. 3

2. 2

3. 1

4. 0

Subtopic:  Introduction, Classification and Nomenclature |
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The difference between a weak field ligand and a strong field ligand is:

1. Weak field ligands cause higher splitting in the d orbitals than strong field ligands.
2. Weak field ligands cause lower splitting in the d orbitals than strong field ligands.
3. Strong field ligands did not form a complex with metal ion.
4. None of the above.

Subtopic:  VBT, CFT & their Limitations |
 70%
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The crystal field splitting energy is:

1. The heat of formation between the two levels (eg and t2g)
2. The combined pairing energy of the two levels (eg and t2g)
3. The combined energy of the three levels in octahedral 
4. The combined energy of the two levels (eg and t2g

Subtopic:  VBT, CFT & their Limitations |
 58%
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[Cr(NH3)6]3+ is paramagnetic ,while Ni(CN)42- is diamagnetic because:

1. Electrons in the 3d orbitals remain unpaired in Ni(CN)42-
2. Electrons in the 3d orbitals remain unpaired in [Cr(NH3)6]3+
3. Electrons in the 3p orbitals remain unpaired in [Cr(NH3)6]3+
4. Electrons in the 3p orbitals remain unpaired in Ni(CN)42-

Subtopic:  VBT, CFT & their Limitations |
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A solution of [Ni(H2O)6]2+ is green, but a solution of [Ni(CN)4]2– is colorless because:

1. There are paired electrons in [Ni(H2O)6]2+ while all electrons are unpaired in [Ni(CN)4]2–
2. There are unpaired electrons in [Ni(H2O)6]2+ while all electrons are paired in [Ni(CN)4]2–
3. There are unpaired electrons in [Ni(H2O)6]2+ and [Ni(CN)4]2–
4. None of the above.

Subtopic:  Introduction, Classification and Nomenclature |
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[Fe(CN)6]4– and [Fe(H2O)6]2+ are of different colors in dilute solutions because :

1. Higher lattice energy value of [Fe(CN)6]4– as compared to [Fe(H2O)6]2+
2. Higher CFSE value of [Fe(CN)6]4– as compared to [Fe(H2O)6]2+
3. Lower CFSE value of [Fe(CN)6]4– as compared to [Fe(H2O)6]2+
4. Lower lattice energy value of [Fe(CN)6]4– as compared to [Fe(H2O)6]2+

Subtopic:  Introduction, Classification and Nomenclature |
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The nature of bonding in metal carbonyls is -

1. The metal-carbon bonds in metal carbonyls have both σ and π characters.
2. The metal-carbon bonds in metal carbonyls have only σ character.
3. The metal-carbon bonds in metal carbonyls have only π character.
4. The metal-carbon bonds in metal carbonyls have only hydrogen bonding.


 

Subtopic:  Organometallic Complexes & their Uses |
 85%
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The greater value of the stability constant of complex salt indicates   -

1. The greater proportion of products.

2. The greater proportion of reactants

3. Lesser concentration of catalyst at equilibrium

4 . All of the above

Subtopic:  VBT, CFT & their Limitations |
 54%
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