Q. No.A black compound of manganese reacts with a halogen acid to give greenish-yellow gas. When an excess of this gas reacts with an unstable trihalide is formed. In this process, the oxidation state of nitrogen changes from-
1. –3 to +3
2. –3 to 0
3. –3 to +5
4. 0 to –3
Reduction potentials of some ions are given below. Arrange them in decreasing order of oxidising power.
|
Ion |
|||
|
Reduction potential E- /V |
= 1.19V |
= 1.65V |
= 1.74V |
If chlorine gas is passed through a hot NaOH solution, two changes are observed in the oxidation number of chlorine during the reaction. These are ......... and .............
a. 0 to +5
b. 0 to +3
c. 0 to -1
d. 0 to +1
Choose the correct option:
1. (a, b)
2. (b, c)
3. (c, d)
4. (a, c)
Which of the following statements are correct?
| a. | Among halogens, the radius ratio between iodine and fluorine is maximum. |
| b. | Leaving F — F bond, all halogens have weaker X — X bond than X — X' bond in interhalogens. |
| c. | Among interhalogen compounds a maximum number of atoms are present in iodine fluoride. |
| d. | Interhalogen compounds are more reactive than halogen compounds. |
1. (a, b, c)
2. (b, c, d)
3. (a, c, d)
4. (a, b, d)
Which of the following orders are correct as per the properties mentioned against each?
| Column I | Column II | ||
| (a) | As2O3 < SiO2 < P2O3 < SO2 | (i) | Acid strength. |
| (b) | AsH3 < PH3 < NH3 | (ii) | Enthalpy of vaporisation. |
| (c) | S < O < Cl < F | (iii) | More negative electron gain enthalpy. |
| (d) | H2O > H2S > H2Se > H2Te | (iv) | Thermal stability. |
1. (a, b)
2. (b, c)
3. (c, d)
4. (a, d)
Match the formulas of oxides are given in Column I with the type of oxide given in Column II and mark the correct option.
| Column I | Column II | ||
| A. | Pb3O4 | 1. | Neutral oxide |
| B. | N2O | 2. | Acidic oxide |
| C. | Mn2O7 | 3. | Basic oxide |
| D. | Bi2O3 | 4. | Mixed oxide |
Codes:
| Options: | A | B | C | D |
| 1. | 1 | 2 | 3 | 4 |
| 2. | 4 | 1 | 2 | 3 |
| 3. | 3 | 2 | 4 | 1 |
| 4. | 4 | 3 | 1 | 2 |
Match the species given in Column I with the shape given in Column II and mark the correct option.
| Column I (Specie) | Column II (Shape) | ||
| A. | \(\mathrm{SF}_4\) | (I) | Tetrahedral |
| B. | \(\mathrm{BrF}_3\) | (II) | Pyramidal |
| C. | \(\mathrm{BrO}_3^{-}\) | (III) | Sea-saw shaped |
| D. | \(\mathrm{NH}_4^{+}\) | (IV) | Bent T-shaped |
Codes:
| A | B | C | D | |
| 1. | III | II | I | IV |
| 2. | III | IV | II | I |
| 3. | I | II | III | IV |
| 4. | I | IV | III | II |
| Assertion (A): | HI cannot be prepared by the reaction of KI with concentrated H2SO4. |
| Reason (R): | HI has the lowest H—X bond strength among halogen acids. |
| 1. | Both (A) and (R) are True and (R) is the correct explanation of (A). |
| 2. | Both (A) and (R) are True but (R) is not the correct explanation of (A). |
| 3. | (A) is True but (R) is False. |
| 4. | (A) is False but (R) is True. |
| Assertion (A): | NaCl reacts with concentrated H2SO4 to give colourless fumes with a pungent smell. But on adding MnO2, the fumes become greenish-yellow. |
| Reason (R): | MnO2 oxidizes HCl to chlorine gas which is greenish-yellow. |
| 1. | Both (A) and (R) are True and (R) is the correct explanation of (A). |
| 2. | Both (A) and (R) are True but (R) is not the correct explanation of (A). |
| 3. | (A) is True but (R) is False. |
| 4. | (A) is False but (R) is True. |
On addition of conc. to a chloride salt, colourless fumes are evolved but in case of iodide salt, violet fumes come out. This is because:
| 1. | reduces HI to | 2. | HI is of violet colour |
| 3. | HI gets oxidised to | 4. | HI changes to HI |
© 2025 GoodEd Technologies Pvt. Ltd.