When 2-Bromopentane reacts with ethanolic KOH, the main product that is formed is:

Phenylacetylene undergoes a reaction with dilute H₂SO₄ in the presence of HgSO₄ to yield:
 

1.		2.
3.		4.

Compound 'A' on chlorination gives compound 'B'. 'B' reacts with alc. KOH to give gas 'C' which decolorizes Baeyer reagent. Ozonolysis of compound 'C' gives only HCHO compound. Compound 'A' is

The reagent used to convert propene to 1-propanol is:

1. H₂O, H₂SO₄

2. B₂H₆, H₂O₂, OH^–

3. Hg(OAc)₂, NaBH₄/H₂O

4. Aq. KOH

On ozonolysis, the alkene that gives the following product is:

1.
2.	\(\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}=\mathrm{CHCH}_2 \mathrm{CH}_3\)
3.	\(\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}=\mathrm{CHCH}_3\)
4.

The compound  on reaction with NaIO₄ in the presence of KMnO₄ gives:

1. CH₃COCH₃

2. CH₃COCH₃ + CH₃COOH

3. CH₃COCH₃ + CH₃CHO

4. CH₃CHO + CO₂

The reaction of HBr with propene in the presence of peroxide gives:

1. 3-bromopropane

2. Allyl bromide

3. n-propyl bromide

4. Isopropyl bromide 

Which one of the following alkenes will react faster with H₂ under catalytic hydrogenation conditions:
 

1.		2.
3.		4.

[R = Alkyl substituent]

Products of the following reaction:

${\mathrm{CH}}_3\mathrm{C}\equiv {\mathrm{CCH}}_2{\mathrm{CH}}_3\frac{\text{ (i) }{\mathrm{O}}_3}{\text{ (2) Hydrolysis }}\text{ are: }$

1. ${\mathrm{CH}}_3\mathrm{COOH}+{\mathrm{CH}}_3{\mathrm{COCH}}_3$

2. ${\mathrm{CH}}_3\mathrm{COOH}+\mathrm{HOOC}\cdot {\mathrm{CH}}_2{\mathrm{CH}}_3$

3. ${\mathrm{CH}}_3\mathrm{CHO}+{\mathrm{CH}}_3{\mathrm{CH}}_2\mathrm{CHO}$

4. ${\mathrm{CH}}_3\mathrm{COOH}+{\mathrm{CO}}_2$