A method for the identification of primary, secondary and tertiary amines is:

1. Azo-dye test

2. Carbylamine test

3. Hinsberg’s test

4. None of these

Aromatic primary amines cannot be prepared by Gabriel phthalimide synthesis because :

 Predict the product formed when benzenediazonium chloride reacts with hypophosphorous acid and water.

C₆H₅N₂Cl + H₃PO₂ + H₂O → Product

The primary amine is -

1. ${\left({\mathrm{CH}}_3\right)}_2{\mathrm{CHNH}}_2$

2. ${{\mathrm{CH}}_3\left({\mathrm{CH}}_2\right)}_2\mathrm{NH}-{\mathrm{CH}}_3$

3. ${{\mathrm{CH}}_3\left({\mathrm{CH}}_2\right)}_2\mathrm{N}{\left({\mathrm{CH}}_3\right)}_2$

4. None of the above

Which of the following is a secondary amine is -

$1.<mspace\; width="1em"></mspace>{\mathrm{CH}}_3{\left({\mathrm{CH}}_2\right)}_2{\mathrm{NH}}_2<mspace\; width="1em"></mspace>$
$2.<mspace\; width="1em"></mspace>{\left({\mathrm{CH}}_3{\mathrm{CH}}_2\right)}_2{\mathrm{NCH}}_3<mspace\; width="1em"></mspace>$
$3.<mspace\; width="1em"></mspace>{\mathrm{C}}_6{\mathrm{H}}_5{\mathrm{NHCH}}_3$
$4.<mspace\; width="1em"></mspace>{\left({\mathrm{CH}}_3\right)}_3{\mathrm{NH}}_2$

The tertiary amine is-

$1.<mspace\; width="1em"></mspace>{\left({\mathrm{CH}}_3{\mathrm{CH}}_2\right)}_2{\mathrm{NCH}}_3<mspace\; width="1em"></mspace>$
$2.<mspace\; width="1em"></mspace>{\left({\mathrm{CH}}_3\right)}_3{\mathrm{NH}}_2<mspace\; width="1em"></mspace>$
$3.<mspace\; width="1em"></mspace>\mathrm{m}-{\mathrm{BrC}}_6{\mathrm{H}}_4{\mathrm{NH}}_2$
$4.<mspace\; width="1em"></mspace>\mathrm{None\; of<mspace\; width="1em"></mspace>}\mathrm{the\; above}$

Which of the following tests is used to distinguish aniline from benzylamine?

1. Nitrous acid.

2. Reduction Reaction

3. Hinsberg reagent

4. Lucas test

The chemical test used to distinguish between aniline and N-methyl aniline is:

1. Carbylamine test 

2. Hoffmann bromamide reaction

3. Acetylation

4. None of above

The chemical test used to distinguish between methylamine and dimethylamine is:

1. Hoffmann bromamide reaction

2. Hinsberg's reagent 

3. Carbylamine test

4. Both 2 and 3

X, Y, and Z in the above sequence are:

1. X= Fe/HCl, Y= ${\mathrm{Br}}_2/{\mathrm{FeCl}}_3$, and Z = ${\mathrm{H}}_2\mathrm{O}$/ warm

2. X= ${\mathrm{Br}}_2/{\mathrm{FeCl}}_3$, Y= Fe/HCl, and Z = ${\mathrm{H}}_2\mathrm{O}$/ warm

3.  X= $\mathrm{HBr}/<mspace\; width="1em"></mspace>\mathrm{hv}$, Y= Fe/HCl, and Z = ${\mathrm{H}}_3{\mathrm{PO}}_2$

4. X = $\mathrm{HBr}/<mspace\; width="1em"></mspace>\mathrm{hv}$ Y = ${\mathrm{Br}}_2/{\mathrm{FeCl}}_3$, and Z = ${\mathrm{H}}_3{\mathrm{PO}}_2$