If the bombardment of α-particle on \(N_{7}^{14}\)  emits protons, then new atom will be:
1. \(O_{8}^{17}\)

2. \(O_{8}^{16}\)

3. \(C_{6}^{14}\)$\mathrm{}$

4. Ne

If the half-life of a substance is 77 days then it's decay constant (days^-1) will be:

1. $\frac{d\left[B{r}^{-}\right]}{dt}=-\frac{3}{5}\frac{d\left[B{r}_2\right]}{dt}$

2. $\frac{d\left[B{r}^{-}\right]}{dt}=\frac{3}{5}\frac{d\left[B{r}_2\right]}{dt}$

3. $\frac{d\left[B{r}^{-}\right]}{dt}=-\frac{5}{3}\frac{d\left[B{r}_2\right]}{dt}$

4. $\frac{d\left[B{r}^{-}\right]}{dt}=\frac{5}{3}\frac{d\left[B{r}_2\right]}{dt}$

₉₂U²³⁵, nucleus absorb a neutron and disintegrate in ₅₄Xe¹³⁹, ₃₈Sr⁹⁴ and x . The product x is:

1. 3 - neutrons

2. 2 - neutrons

3. α - particle

4. β - particle

$\mathrm{In\; the\; reaction,\; 3}\mathrm{A}\to 2\mathrm{B\; the}$ rate of reaction $\frac{+\mathrm{d}\left[\mathrm{B}\right]}{\mathrm{dt}}$ $$ is equal to:-

1. $-\frac{3}{2}\frac{\mathrm{d}\left[\mathrm{A}\right]}{\mathrm{dt}}$

2. $-\frac{2}{3}\frac{\mathrm{d}\left[\mathrm{A}\right]}{\mathrm{dt}}$

3. $-\frac{1}{3}\frac{\mathrm{d}\left[\mathrm{A}\right]}{\mathrm{dt}}$

4. $+2\frac{\mathrm{d}\left[\mathrm{A}\right]}{\mathrm{dt}}$

$2\mathrm{A}$ $\to$ $\mathrm{B}$ $+$ $\mathrm{C}$; It would be a zero-order reaction when:

If at a given instant, for the reaction 2N₂O₅ → 4NO₂ + O₂ rate and rate constant are 1.02 × 10^-4  and 3.4 × 10^-5 sec ^-1 respectively, then the concentration of ${\mathrm{N}}_2{\mathrm{O}}_5$ at that time will be: 

1. 1.732 mol L⁻¹

2. 3.0 mol L⁻¹

3. $1.02$ $\times$ ${10}^{-4}$ mol L⁻¹

4. $3.4$ $\times$ ${10}^5$ mol L⁻¹

When a biochemical reaction is carried out in a laboratory outside the human body in the absence of an enzyme, then the rate of reaction obtained is ${10}^{-6}$ times. The activation energy of a reaction in the presence of an enzyme is:

1. $\frac{6}{RT}$
2. P is required.
3. Different from $E_a$ obtained in the laboratory.
4. Data is insufficient.

The activation energy for a simple chemical reaction A → B is E_a in a forward direction. The activation energy for the reverse reaction:

1. Is negative of E_a

2. Is always less than E_a

3. Can be less than or more than E_a

4. Is always double of E_a

The reaction A → B follows first-order kinetics. The time taken for 0.8 mol of A to produce 0.6 mol of B is 1 hour. The time taken for the conversion of 0.9 mol of A to produce 0.675 mol of B will be: