4d, 5p, 5f and 6p orbitals are arranged in the order of decreasing energy. The correct option is:

1.  5f>6p>4d>5p

2.  5f>6p>5p>4d

3.  6p>5f>5p>4d

4.  6p>5f>4d>5p

The incorrect statement among the following is

1. Total orbital angular momentum of an electron in 's' orbital is equal to zero.

2. An orbital is designated by three quantum numbers, while an electron in an atom is designated by four quantum numbers.

3. The electronic configuration of N atom is 
       

4. The value of m for d_z² is zero.

The element Z = 114 has been discovered recently. 
It will belong to which of the following family/group and electronic configuration.
1. $Carbon family\left[Rn\right]5 f^{14} 6d^{10}7s^{2}7p^2$
2. $Oxygen family\left[Rn\right]5 f^{14} 6d^{10}7s^{2}7p^4$
3. $Nitrogen family\left[Rn\right]5 f^{14} 6d^{10}7s^{2}7p^6$
4. $Ha\log en family\left[Rn\right]5 f^{14} 6d^{10}7s^{2}7p^5$

How many electrons can fit in the subshell for which n = 3 and l = 1?
1.  2
2.  6
3.  10
4.  14

Which is the correct order of increasing energy of the listed orbital’s in the atom of titanium?
1. 3s 4s 3p 3d
2. 4s 3s 3p 3d
3. 3s 3p 3d 4s
4. 3s 3p 4s 3d

If n = 6, the correct sequence for the filling of electrons will be

1. $\mathrm{ns} \stackrel{}{\to } \left(\mathrm{n}-1\right) \mathrm{d} \stackrel{}{\to } \left(\mathrm{n}-2\right) \mathrm{f} \stackrel{}{\to } \mathrm{np}$

2. $\mathrm{ns} - \left(\mathrm{n}-2\right) \mathrm{f} \stackrel{}{\to } \mathrm{np} \stackrel{}{\to } \left(\mathrm{n}-1\right) \mathrm{d}$

3. $\mathrm{ns} - \mathrm{np} \stackrel{}{\to } \left(\mathrm{n}-1\right)\mathrm{d} \stackrel{}{\to } \left(\mathrm{n}-2\right) \mathrm{f}$

4. $\mathrm{ns} \stackrel{}{\to } \left(\mathrm{n}-2\right) \mathrm{f} \stackrel{}{\to } \left(\mathrm{n}-1\right) \mathrm{d} \stackrel{}{\to } \mathrm{np}$