- 1(current)
Q. No.The quantum numbers of four electrons are given below:
I. n=4; l=2; \(m_l\)=-2; s=-\(\frac1{2}\)
II. n=3; l=2; \(m_l\)=1; s=+\(\frac1{2}\)
III. n=4; l=1; \(m_l\)=0; s=+\(\frac1{2}\)
IV. n=3; l=1; \(m_l\)=-1; s=+\(\frac1{2}\)
The correct decreasing order of energy of these electrons is:
1. IV>II>III>I
2. I>III>II>IV
3. III>I>II>IV
4. I>II>III>IV
I. n=4; l=2; \(m_l\)=-2; s=-\(\frac1{2}\)
II. n=3; l=2; \(m_l\)=1; s=+\(\frac1{2}\)
III. n=4; l=1; \(m_l\)=0; s=+\(\frac1{2}\)
IV. n=3; l=1; \(m_l\)=-1; s=+\(\frac1{2}\)
The correct decreasing order of energy of these electrons is:
1. IV>II>III>I
2. I>III>II>IV
3. III>I>II>IV
4. I>II>III>IV
Subtopic: Â Pauli's Exclusion Principle & Hund's Rule |Â AUFBAU Principle |
 77%
From NCERT
NEET - 2024
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Sorry!! currently, the explanation for the question is not provided. If you need further help, please email at support@neetprep.com with subject: Explanation Missing for Question Id: 468860
Subtopic: Â Pauli's Exclusion Principle & Hund's Rule |
 69%
From NCERT
AIPMT - 1998
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NEET 2026 - Target Batch - Vital
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NEET 2026 - Target Batch - Vital
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Q. No.
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