The element Z = 114 has been discovered recently. 
It will belong to which of the following family/group and electronic configuration.
1. Carbon familyRn5 f14 6d107s27p2
2. Oxygen familyRn5 f14 6d107s27p4
3. Nitrogen familyRn5 f14 6d107s27p6
4. Halogen familyRn5 f14 6d107s27p5

Subtopic:  AUFBAU Principle |
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How many electrons can fit in the subshell for which n = 3 and l = 1?
1.  2
2.  6
3.  10
4.  14

Subtopic:  AUFBAU Principle |
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Which of the following statements is wrong?

1. The uncertainty principle is x·ph4π

2. Half-filled and fully filled orbitals have greater stability due to greater exchange energy,

greater symmetry, and a more balanced arrangement.

3. The energy of the 2s orbital is less than the energy of the 2p orbital in the case of hydrogen-like atoms.

4. De-Broglie's wavelength is given by λ=hmv, where m= mass of the particle, v = group velocity of the particle.

Subtopic:  De Broglie Equation |
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A pair of d-orbitals having electron density along the axes is

1. dz2, dxz

2. dxz, dzy

3. dz2, dx2-y2

4. dxy, dx2-y2

Subtopic:  Shell & Subshell |
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The incorrect statement among the following is

1. Total orbital angular momentum of an electron in 's' orbital is equal to zero.

2. An orbital is designated by three quantum numbers, while an electron in an atom is designated by four quantum numbers.

3. The electronic configuration of N atom is 
       

4. The value of m for dz2 is zero.

Subtopic:  AUFBAU Principle |
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Two electrons occupying the same orbital are distinguished by?
1. Magnetic quantum number
2. Azimuthal quantum number
3. Spin quantum number
4. Principal quantum number
Subtopic:  Quantum Numbers & Schrodinger Wave Equation |
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Which is the correct order of increasing energy of the listed orbital’s in the atom of titanium?
1. 3s 4s 3p 3d
2. 4s 3s 3p 3d
3. 3s 3p 3d 4s
4. 3s 3p 4s 3d

Subtopic:  AUFBAU Principle |
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What is the maximum number of orbitals that can be identified with the following quantum numbers?
n = 3, l = 1, m = 0
1. 1
2. 2
3. 3
4. 4

Subtopic:  Quantum Numbers & Schrodinger Wave Equation |
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Calculate the energy in corresponding to light of wavelength 45 nm :
(Planck's constant h = 6.63 × 10–34 Js: speed of light c = 3 × 108 ms–1)
1. 6.67 x 1015 J
2. 6.67 x 1011 J
3. 4.42 x 10-15 J
4. 4.42 x 10-18 J

Subtopic:  Planck's Theory |
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The value of Planck's constant is 6.63 × 10–34 Js. The speed of light is 3 × 1017 nm s–1. Which value is closest to the wavelength in nanometer of a quantum of light with frequency of 6 × 1015 s–1 ?
 
1. 25
2. 50
3. 75
4. 10
Subtopic:  Photo Electric Effect |
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