# What is the maximum number of orbitals that can be identified with the following quantum numbers? n = 3, l = 1, m = 0 1. 1 2. 2 3. 3 4. 4

Subtopic:  Quantum Numbers & Schrodinger Wave Equation |
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Calculate the energy in corresponding to light of wavelength 45 nm :
(Planck's constant h = 6.63 × 10–34 Js: speed of light c = 3 × 108 ms–1)
1. 6.67 x 1015 J
2. 6.67 x 1011 J
3. 4.42 x 10-15 J
4. 4.42 x 10-18 J

Subtopic:  Planck's Theory |
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The value of Planck's constant is 6.63 × 10–34 Js. The speed of light is 3 × 1017 nm s–1. Which value is closest to the wavelength in nanometer of a quantum of light with frequency of 6 × 1015 s–1 ?

1. 25
2. 50
3. 75
4. 10
Subtopic:  Photo Electric Effect |
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What is the maximum numbers of electrons that can be associated with the following set of quantum numbers?
n = 3, l = 1 and m = –1.
1. 6
2. 4
3. 2
4. 10

Subtopic:  Quantum Numbers & Schrodinger Wave Equation |
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Based on equation E = –2.178 × 10–18J, $\frac{{\mathrm{Z}}^{2}}{{\mathrm{n}}^{2}}$ certain conclusions are written. Which of them is not correct ?
1. Larger the value of n, larger is the orbit radius.
2. Equation can be used to calculate the change in energy when the electron changes orbit.
3. For n = 1, the electron has a more negative energy than it does for n = 6 which means that the electron is more loosely bound in the smallest allowed orbit.
4. The negative sign in equation simply means that the energy of electron bound to the nucleus is lower than what it would be if the electrons were at an infinite distance from the nucleus.

Subtopic:  Bohr's Theory |
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Maximum number of electrons in a sub shell with l = 3 and n = 4 is

1. 14

2. 16

3. 10

4. 12

Subtopic:  Quantum Numbers & Schrodinger Wave Equation |
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The correct set of four quantum numbers for the valence electron of a rubidium atom (Z =37) is

1. $5,1,1,+\frac{1}{2}$

2. $6,0,0,+\frac{1}{2}$

3. $5,0,0,+\frac{1}{2}$

4. $5,1,0,+\frac{1}{2}$

Subtopic:  Quantum Numbers & Schrodinger Wave Equation |
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The total number of atomic orbitals in fourth energy level of an atom is

1.  16
2.  32
3.  4
4.  8

Subtopic:  Bohr's Theory |
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The energies E1 and E2 of two radiations are 25 eV and 50 eV respectively. The relation between their wavelenghs i.e., ${\mathrm{\lambda }}_{1}$ and ${\mathrm{\lambda }}_{2}$ will be

1.  ${\mathrm{\lambda }}_{1}=2{\mathrm{\lambda }}_{2}$

2.  ${\mathrm{\lambda }}_{1}=4{\mathrm{\lambda }}_{2}$

3.  ${\mathrm{\lambda }}_{1}=\frac{1}{2}{\mathrm{\lambda }}_{2}$

4.  ${\mathrm{\lambda }}_{1}={\mathrm{\lambda }}_{2}$

Subtopic:  Bohr's Theory |
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If n = 6, the correct sequence for the filling of electrons will be

1.

2.

3.

4.

Subtopic:  AUFBAU Principle |
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