Given the following hydrocarbon:

The state of hybridisation of carbons marked 2, 3, 5 and 6 in the following hydrocarbon are, respectively :

1. sp, sp³, sp² and sp³

2. sp³, sp², sp² and sp

3. sp, sp², sp² and sp³

4. sp, sp² sp³ and sp²

Which among the following compounds has higher hydration energy than the lattice energy?

1. BaSO₄                           

2. MgSO₄

3. CaSO₄                           

4. SrSO₄

Which of the following species has a zero dipole moment?

$\left(\mathrm{i}\right)$ ${\mathrm{CO}}_2$ (ii) ${\mathrm{COCl}}_2$ (iii) ${\mathrm{CH}}_2$ ${\mathrm{Cl}}_2$ (iv) ${\mathrm{BCl}}_3$

Which of the following is a pair of polar molecules?

1. ${\mathrm{CO}}_2$ $\mathrm{and}$ ${\mathrm{H}}_2\mathrm{O}$

2. ${\mathrm{BF}}_3$ $\mathrm{and}$ ${\mathrm{PCl}}_3$

3. ${\mathrm{SO}}_2$ $\mathrm{and}$ ${\mathrm{SCl}}_2$

4. ${\mathrm{CS}}_2$ $\mathrm{and}$ ${\mathrm{SO}}_3$

The incorrect order of lattice energy among the following set is:

1. ${\mathrm{AlF}}_3>{\mathrm{MgF}}_2$         

2. ${\mathrm{Li}}_3\mathrm{N}>{\mathrm{Li}}_2\mathrm{O}$

3. $\mathrm{NaCl}>\mathrm{LiF}$           

4. $\mathrm{TiC}>\mathrm{ScN}$

The incorrect order of the force of attraction among the given species is :

1. HI > HBr> ${\mathrm{Cl}}_2$

2. ${\mathrm{CCl}}_4>{\mathrm{CH}}_2{\mathrm{Cl}}_2>{\mathrm{CH}}_3\mathrm{Cl}>{\mathrm{CH}}_4$

3. n- Pentane > iso-Pentane > neo-Pentane

4. ${\mathrm{OH}}_2>\mathrm{O}{\left({\mathrm{CH}}_3\right)}_2>{\mathrm{OBr}}_2$

Molecule that has $\mu$ (observed) greater than $\mu$ (theoretical) is : 

1.	CHCl3	2.
3.		4.

A gas that should not be collected over water is-

1. ${\mathrm{H}}_2$

2. ${\mathrm{N}}_2$

3. ${\mathrm{CH}}_4$

4. HCl

The compound that has the lowest boiling point is:

The correct statement about hydrolysis of ${\mathrm{BCl}}_3$ and ${\mathrm{NCl}}_3$ is-

1. ${\mathrm{NCl}}_3$ is hydrolysed and gives $\mathrm{HOCl}$ but ${\mathrm{BCl}}_3$ is not hydrolysed

2. Both ${\mathrm{NCl}}_3$ and ${\mathrm{BCl}}_3$ on hydrolysis gives $\mathrm{HCl}$

3. ${\mathrm{NCl}}_3$ on hydrolysis gives $\mathrm{HOCl}$  but ${\mathrm{BCl}}_3$ gives $\mathrm{HCl}$

4. Both ${\mathrm{NCl}}_3$ and ${\mathrm{BCl}}_3$ on hydrolysis gives $\mathrm{HOCl}$