The correct bond angle for \(\mathrm{sp}^2\) hybridization is:

1. \(90^\circ\) 2. \(120^\circ\)
3. \(180^\circ\) 4. \(109^\circ\)

Subtopic:  Hybridisation |
 88%
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The electronic configurations of the elements A, B, and C are given below.

A  = 1s2  2s2  2p6
B  = 1s2  2s2  2p6  3s2  3p3
C =  1s2  2s2  2p6  3s2  3p5

The stable form of A may be represented by the formula:

1. A 2. A2
3. A3 4. A4
Subtopic:  Covalent Bond |
 81%
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The electronic configurations of the elements A, B, and C are given below.

A  = 1s2  2s2  2p6
B  = 1s2  2s2  2p6  3s2  3p3
C =  1s2  2s2  2p6  3s2  3p5

The stable form of C may be represented by the formula : 

1. C 2. C2
3. C3 4. C4
Subtopic:  Covalent Bond |
 78%
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The electronic configurations of the elements A, B, and C are given below.

A  = 1s2  2s2  2p6
B  = 1s2  2s2  2p6  3s2  3p3
C =  1s2  2s2  2p6  3s2  3p5

The bond between B and C will be : 

1. Ionic. 2. Covalent.
3. Hydrogen. 4. Coordinate.
Subtopic:  Covalent Bond |
 78%
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From the perspective of molecular orbital theory, which statement is false?

1. Be2 is not a stable molecule.

2. He2 is not stable but He2+ is expected to exist.

3. Bond strength of N2 is maximum amongst the homonuclear diatomic molecules belonging to the second period.

4. The order of energies of molecular orbitals in N2 molecule is: 

σ2s<σ2s*<σ2pz<(π2pxπ2py)
<(π2px*π2py*)<σ2pz*

Subtopic:  M.O.T |
 75%
From NCERT
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What is the correct sequence of bond order for the specified species?

1. \(\mathrm{O}^-_2>\mathrm{O}_2>\mathrm{O}^+_2\) 2. \(\mathrm{O}^-_2<\mathrm{O}_2<\mathrm{O}^+_2\)
3. \(\mathrm{O}^-_2>\mathrm{O}_2<\mathrm{O}^+_2\) 4. \(\mathrm{O}^-_2<\mathrm{O}_2>\mathrm{O}^+_2\)
Subtopic:  M.O.T |
 83%
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The shape of  AsF5 is:

1. Pentagonal bipyramidal. 2. Trigonal bipyramidal.
3. Distorted tetrahedral. 4. Square pyramidal.

Subtopic:  V.S.E.P.R & V.B.T |
 74%
From NCERT
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The incorrect statement about NH3 and H2O is :

1. The bond angle in NH3 is less than in H2O.

2. Both have distorted tetrahedral geometries.

3. The bond angle in H2O is less than in NH3.

4. Both are sp3 hybridized. 

Subtopic:  Hybridisation |
 69%
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The relative order of stability of the following species: \(\mathrm{O}_2,\mathrm{O}^+_2,\mathrm{O}^-_2~\mathrm{and}~\mathrm{O}^{2-}_2\) is -

1. \(\mathrm{O}^+_2>\mathrm{O}_2>\mathrm{O}^-_2>\mathrm{O}^{2-}_2\) 2. \(\mathrm{O}^{2-}_2>\mathrm{O}_2>\mathrm{O}^-_2>\mathrm{O}^{+}_2\)
3. \(\mathrm{O}_2>\mathrm{O}^+_2>\mathrm{O}^-_2>\mathrm{O}^{2-}_2\) 4. \(\mathrm{O}_2>\mathrm{O}^{2-}_2>\mathrm{O}^-_2>\mathrm{O}^{+}_2\)

Subtopic:  M.O.T |
 82%
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The plus and negative sign of the orbitals mean:

1. Wave function.

2. Probability density.

3. Quantum number of orbitals.

4. Frequency of orbitals.

Subtopic:  M.O.T |
 62%
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