Which of the following atomic orbitals would have the greatest overlap to form the strongest covalent bond?

1.	2s-2s (σ)	2.	2s-2p (σ)
3.	2p-2p (π)	4.	2p-2p (σ)

 The 'S' atom among the following that does not have \(\mathrm{sp}^3\) hybridization is

A pair in which both species are not likely to exist is:

A molecule that has an unequal bond length is : 

Amongst ${\mathrm{H}}_2\mathrm{O}, {\mathrm{H}}_2\mathrm{S}, {\mathrm{H}}_2\mathrm{Se} \mathrm{and} {\mathrm{H}}_2\mathrm{Te}$ the one with the highest boiling point is:

1. H₂O because of H-bonding.

2. H₂Te because of higher molecular weight.

3. H₂S because of H-bonding.

4. H₂Se because of lower molecular weight.

The correct order of electronegativity of hybrid orbitals of carbon is:

1. sp > sp² < sp³             

2. sp > sp² > sp³

3. sp < sp² > sp³             

4. sp < sp² < sp³

${\mathrm{H}}_2\mathrm{O}$ has a net dipole moment while
\(BeF_2\) has zero dipole moment because :

1. F is more electronegative than oxygen.

2. Be is more electronegative than oxygen. 

3. ${\mathrm{H}}_2\mathrm{O}$ $$ molecule is linear and \(BeF_2\) is bent.

4. ${\mathrm{BeF}}_2$ molecule is linear and ${\mathrm{H}}_2\mathrm{O}$ is bent.

A molecule among the following with non-zero dipole moment is:

1. ${\mathrm{C}}_6{\mathrm{Cl}}_6$

2. ${\mathrm{C}}_2{\mathrm{Cl}}_6$

3. $\mathrm{C}{\left({\mathrm{CCl}}_3\right)}_4$

4. $:{\mathrm{CCl}}_2$

Which molecule is least likely to form hydrogen bonds? 

The correct geometry and hybridization for XeF₄ are : 

1.  Octahedral, sp³d²

2.  Trigonal bipyramidal, sp³d³

3.  Planar triangle, sp³d³

4.  Square planar, sp³d²