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Q. No.What is the SI unit of \({\large\frac{\text{(magnetic flux)}}{\text{(electric resistance)}}}?\)
1.
volt
2.
ampere
3.
coulomb
4.
volt-second
Subtopic: Magnetic Flux |
58%
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A wire shaped in the form of a right angled triangle \(XYZ\) moves with a uniform velocity in a region of space where there exists a uniform magnetic field \(B,\) acting into the plane. The velocity \(v\) is along the side \(YZ.\) The length \(XY=l.\)
The motional EMF acting along \(XY\) is:
1. \(Blv\)
2. \(Blv\sin\theta\)
3. \(Blv\cos\theta\)
4. zero
The motional EMF acting along \(XY\) is:
1. \(Blv\)
2. \(Blv\sin\theta\)
3. \(Blv\cos\theta\)
4. zero
Subtopic: Self - Inductance |
58%
From NCERT
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A wire shaped in the form of a right angled triangle \(XYZ\) moves with a uniform velocity in a region of space where there exists a uniform magnetic field \(B,\) acting into the plane. The velocity \(v\) is along the side \(YZ.\) The length \(XY=l.\)
The motional EMF acting along \(YZ\) is:
1. \(Blv\sin\theta\)
2. \(Blv\tan\theta\)
3. \(\Large\frac{Blv}{\sin\theta}\)
4. zero
The motional EMF acting along \(YZ\) is:
1. \(Blv\sin\theta\)
2. \(Blv\tan\theta\)
3. \(\Large\frac{Blv}{\sin\theta}\)
4. zero
Subtopic: Motional emf |
71%
From NCERT
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A wire shaped in the form of a right angled triangle \(XYZ\) moves with a uniform velocity in a region of space where there exists a uniform magnetic field \(B,\) acting into the plane. The velocity \(v\) is along the side \(YZ.\) The length \(XY=l.\)
If the wire loop \(XYZ\) has a finite resistance, the induced current flowing through the wire loop will be:
1. clockwise
2. anti-clockwise
3. zero
4. alternating
If the wire loop \(XYZ\) has a finite resistance, the induced current flowing through the wire loop will be:
1. clockwise
2. anti-clockwise
3. zero
4. alternating
Subtopic: Faraday's Law & Lenz Law |
From NCERT
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An inductor of inductance \(10~\text{mH}\) is connected in series with another identical inductor in series with each other. The inductance of the combined system is observed to be \(18~\text{mH}.\) The mutual inductance between the two inductors is:
1. \(1~\text{mH}\)
2. \(2~\text{mH}\)
3. \(4~\text{mH}\)
4. \({\Large\frac{1}{2}}~\text{mH}\)
1. \(1~\text{mH}\)
2. \(2~\text{mH}\)
3. \(4~\text{mH}\)
4. \({\Large\frac{1}{2}}~\text{mH}\)
Subtopic: Mutual Inductance |
68%
From NCERT
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A rectangular loop \((ABCD)\) is placed in a magnitude field where the field in the left half of the loop decreases at the same rate as the field in the right half of the loop increases (at a constant rate): \({\Large\frac{dB_{\mathrm I}}{dt}}=-{\Large\frac{dB_{\mathrm{II}}}{dt}};\) \(B_{\mathrm {I}}\) and \(B_{\mathrm {II}}\) are both normal to the plane of the loop and acting inward. The EMF induced in the loop is:
1. clockwise
2. anticlockwise
3. zero
4. oscillatory
1. clockwise
2. anticlockwise
3. zero
4. oscillatory
Subtopic: Faraday's Law & Lenz Law |
72%
From NCERT
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Two parallel, smooth, horizontal conducting rails are laid at a distance \(2~\text m\) apart. The rails are connected by a \(100~\Omega\) resistance. A conducting rod \(XY\) is slid smoothly over the rails, making electrical contact and moving with a constant velocity of \(10~\text{m/s}.\) A uniform magnetic field \((B)\) of \(10^{-2}~\text T\) acts vertically downward, into the plane.
The emf acting across the rod \(XY\) is:
1. \(1~\text V\)
2. \(2~\text V\)
3. \(0.1~\text V\)
4. \(0.2~\text V\)
The emf acting across the rod \(XY\) is:
1. \(1~\text V\)
2. \(2~\text V\)
3. \(0.1~\text V\)
4. \(0.2~\text V\)
Subtopic: Motional emf |
89%
From NCERT
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Two parallel, smooth, horizontal conducting rails are laid at a distance \(2~\text m\) apart. The rails are connected by a \(100~\Omega\) resistance. A conducting rod \(XY\) is slid smoothly over the rails, making electrical contact and moving with a constant velocity of \(10~\text{m/s}.\) A uniform magnetic field \((B)\) of \(10^{-2}~\text T\) acts vertically downward, into the plane.
The current flowing through the \(100~\Omega\) resistance is:
1. \(0.01~\text A\)
2. \(0.02~\text A\)
3. \(1~\text{mA}\)
4. \(2~\text{mA}\)
The current flowing through the \(100~\Omega\) resistance is:
1. \(0.01~\text A\)
2. \(0.02~\text A\)
3. \(1~\text{mA}\)
4. \(2~\text{mA}\)
Subtopic: Faraday's Law & Lenz Law |
62%
From NCERT
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Two parallel, smooth, horizontal conducting rails are laid at a distance \(2~\text m\) apart. The rails are connected by a \(100~\Omega\) resistance. A conducting rod \(XY\) is slid smoothly over the rails, making electrical contact and moving with a constant velocity of \(10~\text{m/s}.\) A uniform magnetic field \((B)\) of \(10^{-2}~\text T\) acts vertically downward, into the plane.
The force acting on the rod \(XY\) due to the current flowing through it (and the magnetic field) is:
1. \(2\times10^{-5}~\text N\)
2. \(4\times10^{-5}~\text N\)
3. \(2\times10^{-3}~\text N\)
4. \(4\times10^{-3}~\text N\)
The force acting on the rod \(XY\) due to the current flowing through it (and the magnetic field) is:
1. \(2\times10^{-5}~\text N\)
2. \(4\times10^{-5}~\text N\)
3. \(2\times10^{-3}~\text N\)
4. \(4\times10^{-3}~\text N\)
Subtopic: Faraday's Law & Lenz Law |
80%
From NCERT
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The magnetic energy stored in a long current-carrying solenoid, carrying a current of \(2~\text A\) is \(5\times10^{-3}~\text J.\) If the winding is 'doubled' on top of the previous one, and the same current of \(2~\text A\) is passed through both, in the same sense. The stored energy is:
1. \(2.5\times10^{-3}~\text J\)
2. \(10\times10^{-3}~\text J\)
3. \(20\times10^{-3}~\text J\)
4. \(80\times10^{-3}~\text J\)
1. \(2.5\times10^{-3}~\text J\)
2. \(10\times10^{-3}~\text J\)
3. \(20\times10^{-3}~\text J\)
4. \(80\times10^{-3}~\text J\)
Subtopic: Self - Inductance |
52%
From NCERT
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