- 1(current)
Q. No.AB is a \(20\) \(\Omega\) resistor with a tapping point C that can be moved along AB. The resistances in AC, BC are proportional to the lengths AC, BC. Initially, C is at the mid-point of AB and the circuit is switched on.
If the tapping point C is moved so that the length BC is reduced to half its initial value, then the voltage across the \(15\) \(\Omega\) resistor,
If the tapping point C is moved so that the length BC is reduced to half its initial value, then the voltage across the \(15\) \(\Omega\) resistor,
| 1. | increases by \(1\) V |
| 2. | decreases by \(1\) V |
| 3. | increases by \(3\) V |
| 4. | decreases by \(3\) V |
Subtopic: Â Kirchoff's Voltage Law |
From NCERT
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The current flowing through the left \(20~\Omega\) resistor is:
| 1. | \(1\) A | 2. | \(0.5\) A |
| 3. | \(2.5\) A | 4. | \(3\) A |
Subtopic: Â Kirchoff's Voltage Law |
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All the cells, shown in the figure below, are of \(2\) V, and all the resistances are \(1\) \(\Omega\). When a potential difference \(V\) is applied between A and B, the current through the circuit doubles compared to the situation when the potential difference is made zero.
Then,
Then,
| 1. | \(V=2\) volt, positive at A. |
| 2. | \(V=2\) volt, negative at A. |
| 3. | \(V=6\) volt, positive at A. |
| 4. | \(V=6\) volt, negative at A. |
Subtopic: Â Kirchoff's Voltage Law |
From NCERT
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