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The current in a wire varies with time according to the equation \(I=(4+2t),\) where \(I\) is in ampere and \(t\) is in seconds. The quantity of charge which has passed through a cross-section of the wire during the time \(t=2\) s to \(t=6\) s will be:

1. | \(60\) C | 2. | \(24\) C |

3. | \(48\) C | 4. | \(30\) C |

Subtopic: Current & Current Density |

83%

From NCERT

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A charged particle having drift velocity of \(7.5\times10^{-4}~\text{ms}^{-1}\) in an electric field of \(3\times10^{-10}~\text{Vm}^{-1}\), has mobility of:

1. \(2.5\times 10^{6}~\text{m}^2\text{V}^{-1}\text{s}^{-1}\)

2. \(2.5\times 10^{-6}~\text{m}^2\text{V}^{-1}\text{s}^{-1}\)

3. \(2.25\times 10^{-15}~\text{m}^2\text{V}^{-1}\text{s}^{-1}\)

4. \(2.25\times 10^{15}~\text{m}^2\text{V}^{-1}\text{s}^{-1}\)

Subtopic: Current & Current Density |

82%

From NCERT

NEET - 2020

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Drift velocity \(v_d\) varies with the intensity of electric field as per the relation:

1. \(v_{d} \propto E\)

2. \(v_{d} \propto \frac{1}{E}\)

3. \(v_{d}= \text{constant}\)

4. \(v_{d} \propto E^2\)

Subtopic: Current & Current Density |

78%

From NCERT

PMT - 1981

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The resistance of a wire is \(R\) ohm. If it is melted and stretched to \(n\) times its original length, its new resistance will be:

1. \(nR\)

2. \(\frac{R}{n}\)

3. \(n^2R\)

4. \(\frac{R}{n^2}\)

Subtopic: Derivation of Ohm's Law |

82%

From NCERT

NEET - 2017

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Two solid conductors are made up of the same material and have the same length and the same resistance. One of them has a circular cross-section of area ${A}_{1}$ and the other one has a square cross-section of area ${A}_{2}$. The ratio ${A}_{1}/{A}_{2}$ is:

1. | \(1.5\) | 2. | \(1\) |

3. | \(0.8\) | 4. | \(2\) |

Subtopic: Derivation of Ohm's Law |

82%

From NCERT

NEET - 2020

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The dependence of resistivity \((\rho)\) on the temperature \((T)\) of a semiconductor is, roughly, represented by:

1. | 2. | ||

3. | 4. |

Subtopic: Derivation of Ohm's Law |

64%

From NCERT

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The equivalent resistance between \(A\) and \(B\) for the mesh shown in the figure is:

1. | \(7.2\) \(\Omega\) | 2. | \(16\) \(\Omega\) |

3. | \(30\) \(\Omega\) | 4. | \(4.8\) \(\Omega\) |

Subtopic: Combination of Resistors |

87%

From NCERT

NEET - 2020

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A potential divider is used to give outputs of \(2~\text{V}\) and \(3~\text{V}\) from a \(5~\text{V}\) source, as shown in the figure.

Which combination of resistances, from the ones given below, \(R_1, R_2, ~\text{and}~R_3\) give the correct voltages?1. | \({R}_1=1~\text{k} \Omega, {R}_2=1 ~\text{k} \Omega, {R}_3=2 ~\text{k} \Omega\) |

2. | \({R}_1=2 ~\text{k} \Omega, {R}_2=1~\text{k} \Omega, {R}_3=2~\text{k} \Omega\) |

3. | \({R}_1=1 ~\text{k} \Omega, {R}_2=2~ \text{k} \Omega, {R}_3=2~ \text{k} \Omega\) |

4. | \({R}_1=3~\text{k} \Omega, {R}_2=2~\text{k} \Omega, {R}_3=2~ \text{k} \Omega\) |

Subtopic: Combination of Resistors |

79%

From NCERT

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In the circuit shown in the figure, the effective resistance between \(A\) and \(B\) is:

1. \(2~\Omega\)

2. \(4~\Omega\)

3. \(6~\Omega\)

4. \(8~\Omega\)

Subtopic: Combination of Resistors |

79%

From NCERT

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The effective resistance between points \(P\) and \(Q\) of the electrical circuit shown in the figure is:

1. | \(\frac{2 R r}{\left(R + r \right)}\) | 2. | \(\frac{8R\left(R + r\right)}{\left( 3 R + r\right)}\) |

3. | \(2r+4R\) | 4. | \(\frac{5R}{2}+2r\) |

Subtopic: Combination of Resistors |

76%

From NCERT

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