Q. No.A wire of resistance \(R\) is cut into \(8\) equal pieces. From these pieces two equivalent resistance are made by adding four of these together in parallel. Then these two sets are added in series. The net effective resistance of the combination is:
| 1. | \(\dfrac{R}{16}\) | 2. | \(\dfrac{R}{8}\) |
| 3. | \(\dfrac{R}{64}\) | 4. | \(\dfrac{R}{32}\) |
Subtopic: Combination of Resistors |
60%
From NCERT
NEET - 2025
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A wire of length \('l'\) and resistance \(100 ~\Omega\) is divided into \(10\) equal parts. The first \(5\) parts are connected in series while the next \(5\) parts are connected in parallel. The two combinations are again connected in series. The resistance of this final combination is:
| 1. | \(52~ \Omega\) | 2. | \(55~ \Omega\) |
| 3. | \(60 ~\Omega\) | 4. | \(26~ \Omega\) |
Subtopic: Combination of Resistors |
68%
From NCERT
NEET - 2024
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The equivalent resistance \(R_{AB}\) between points \(A\) and \(B\) in the given network is:
| 1. | \(1R\) | 2. | \({\dfrac35}R\) |
| 3. | \({\dfrac78}R\) | 4. | \({\dfrac58}R\) |
Subtopic: Combination of Resistors |
72%
From NCERT
NEET - 2024
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\(10\) resistors, each of resistance \(R\) are connected in series to a battery of \(E\) and negligible internal resistance. Then those are connected in parallel to the same battery, the current is increased \(n\) times. The value of \(n\) is:
1. \(1000\)
2. \(10\)
3. \(100\)
4. \(1\)
1. \(1000\)
2. \(10\)
3. \(100\)
4. \(1\)
Subtopic: Combination of Resistors |
69%
From NCERT
NEET - 2023
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A network of resistors is connected across a \(10~\text{V}\) battery with an internal resistance of \(1~\Omega\) as shown in the circuit diagram. The equivalent resistance of the circuit is:
| 1. | \(\dfrac{17}{3}~\Omega\) | 2. | \(\dfrac{14}{3}~\Omega\) |
| 3. | \(\dfrac{12}{7}~\Omega\) | 4. | \(\dfrac{14}{7}~\Omega\) |
Subtopic: Combination of Resistors |
75%
From NCERT
NEET - 2022
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The equivalent resistance of the infinite network given below is:
1. \(2~\Omega\)
2. \((1+\sqrt2)~\Omega\)
3. \((1+\sqrt3)~\Omega\)
4. \((1+\sqrt5)~\Omega\)
1. \(2~\Omega\)
2. \((1+\sqrt2)~\Omega\)
3. \((1+\sqrt3)~\Omega\)
4. \((1+\sqrt5)~\Omega\)
Subtopic: Combination of Resistors |
54%
From NCERT
NEET - 2022
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The effective resistance of a parallel connection that consists of four wires of equal length, equal area of cross-section, and same material is \(0.25~\Omega\). What will be the effective resistance if they are connected in series?
1. \(1~\Omega\)
2. \(4~\Omega\)
3. \(0.25~\Omega\)
4. \(0.5~\Omega\)
Subtopic: Combination of Resistors |
72%
From NCERT
NEET - 2021
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The equivalent resistance between \(A\) and \(B\) for the mesh shown in the figure is:
| 1. | \(7.2~\Omega\) | 2. | \(16~\Omega\) |
| 3. | \(30~\Omega\) | 4. | \(4.8~\Omega\) |
Subtopic: Combination of Resistors |
88%
From NCERT
NEET - 2020
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The resistance of a wire is \(R~\Omega\). If it is melted and stretched \(n\) times its original length, its new resistance will be:
1. \(\frac{R}{n}\)
2. \(n^{2}R\)
3. \(\frac{R}{n^{2}}\)
4. \(nR\)
1. \(\frac{R}{n}\)
2. \(n^{2}R\)
3. \(\frac{R}{n^{2}}\)
4. \(nR\)
Subtopic: Combination of Resistors |
80%
From NCERT
NEET - 2017
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A ring is made of a wire having a resistance of \(R_0=12~\Omega.\). Find points \(\mathrm{A}\) and \(\mathrm{B}\), as shown in the figure, at which a current-carrying conductor should be connected so that the resistance \(R\) of the subcircuit between these points equals \(\frac{8}{3}~\Omega\)
| 1. | \(\dfrac{l_1}{l_2} = \dfrac{5}{8}\) | 2. | \(\dfrac{l_1}{l_2} = \dfrac{1}{3}\) |
| 3. | \(\dfrac{l_1}{l_2} = \dfrac{3}{8}\) | 4. | \(\dfrac{l_1}{l_2} = \dfrac{1}{2}\) |
Subtopic: Combination of Resistors |
53%
From NCERT
AIPMT - 2012
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