The resistances of the four arms $$P,Q,R~\text{and}~S$$ in a Wheatstone’s bridge are $$10~\Omega,30~\Omega,30~\Omega$$ and $$90~\Omega$$ respectively. The emf and internal resistance of the cell are $$7~\text{volt}$$ and $$5~\Omega$$ respectively. If the galvanometer resistance is $$50~\Omega$$ the current drawn from the cell will be:
1. $$0.2~\text{A}$$
2. $$0.1~\text{A}$$
3. $$2.0~\text{A}$$
4. $$1.0~\text{A}$$

Subtopic:  Wheatstone Bridge |
76%
From NCERT
AIPMT - 2013
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Three resistances $$\mathrm P$$, $$\mathrm Q$$, and $$\mathrm R$$, each of $$2~\Omega$$ and an unknown resistance $$\mathrm{S}$$ form the four arms of a Wheatstone bridge circuit. When the resistance of $$6~\Omega$$ is connected in parallel to $$\mathrm{S}$$, the bridge gets balanced. What is the value of $$\mathrm{S}$$?

 1 $$2~\Omega$$ 2 $$3~\Omega$$ 3 $$6~\Omega$$ 4 $$1~\Omega$$
Subtopic:  Wheatstone Bridge |
81%
From NCERT
AIPMT - 2007
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