- 1(current)
Q. No.\(\mathrm{A, B}~\text{and}~\mathrm{C}\) are voltmeters of resistance \(R\), \(1.5R\) and \(3R\) respectively as shown in the figure above. When some potential difference is applied between \(\mathrm{X}\) and \(\mathrm{Y}\), the voltmeter readings are \({V}_\mathrm{A}\), \({V}_\mathrm{B}\) and \({V}_\mathrm{C}\) respectively. Then:
| 1. | \({V}_\mathrm{A} ={V}_\mathrm{B}={V}_\mathrm{C}\) | 2. | \({V}_\mathrm{A} \neq{V}_\text{B}={V}_\mathrm{C}\) |
| 3. | \({V}_\mathrm{A} ={V}_\mathrm{B}\neq{V}_\mathrm{C}\) | 4. | \({V}_\mathrm{A} \ne{V}_\mathrm{B}\ne{V}_\mathrm{C}\) |
In the circuit shown cells, \(A\) and \(B\) have negligible resistance. For \(V_A =12 ~\text{V}\), \(R_1 = 500 ~\Omega \), and \(R = 100 ~\Omega \) the galvanometer \((\text{G}) \) shows no deflection. The value of \(V_B\) is:
1. \(4\) V
2. \(2\) V
3. \(12\) V
4. \(6\) V
In the circuit shown in the figure below, if the potential at point \(A\) is taken to be zero, the potential at point \(B\) will be:
1. \(+1\) V
2. \(-1\) V
3. \(+2\) V
4. \(-2\) V
See the electrical circuit shown in this figure. Which of the following is a correct equation for it?
| 1. | \(\varepsilon_1-(i_1+i_2)R-i_1r_1=0\) |
| 2. | \(\varepsilon_2-i_2r_2-\varepsilon_1-i_1r_1=0\) |
| 3. | \(-\varepsilon_2-(i_1+i_2)R+i_2r_2=0\) |
| 4. | \(\varepsilon_1-(i_1+i_2)R+i_1r_1=0\) |
| 1. | flow from \(A\) to \(B\) |
| 2. | flow in the direction which will be decided by the value of \(V\) |
| 3. | be zero |
| 4. | flow from \(B\) to \(A\) |
Kirchhoff’s first and second laws for electrical circuits are consequences of:
| 1. | conservation of energy. |
| 2. | conservation of electric charge and energy respectively. |
| 3. | conservation of electric charge. |
| 4. | conservation of energy and electric charge respectively. |
- 1(current)
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