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A potentiometer circuit has been set up for finding the internal resistance of a given cell. The main battery, used across the potentiometer wire, has an emf of \(2.0~\text{V}\) and negligible internal resistance. The potentiometer wire itself is \(4~\text{m}\) long. When the resistance, \(R\), connected across the given cell, has values of (i) infinity (ii) \(9.5\), the 'balancing lengths, on the potentiometer wire, are found to be \(3~\text{m}\) and \(2.85~\text{m}\), respectively. The value of the internal resistance of the cell is (in ohm):

1. \(0.25\)

2. \(0.95\)

3. \(0.5\)

4. \(0.75\)

Subtopic: Meter Bridge & Potentiometer |

65%

From NCERT

AIPMT - 2014

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A wire of resistance \(4~\Omega\) is stretched to twice its original length. The resistance of a stretched wire would be:

1. | \(4~\Omega\) | 2. | \(8~\Omega\) |

3. | \(16~\Omega\) | 4. | \(2~\Omega\) |

Subtopic: Derivation of Ohm's Law |

83%

From NCERT

AIPMT - 2013

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Internal resistance of a \(2.1~\text{V}\) cell which gives a current of \(0.2~\text{A}\) through a resistance of \(10~\Omega\) is:

1. \(0.5~\Omega\)

2. \(0.8~\Omega\)

3. \(1.0~\Omega\)

4. \(0.2~\Omega\)

1. \(0.5~\Omega\)

2. \(0.8~\Omega\)

3. \(1.0~\Omega\)

4. \(0.2~\Omega\)

Subtopic: EMF & Terminal Voltage |

84%

From NCERT

AIPMT - 2013

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The resistances of the four arms \(P,Q,R~\text{and}~S\) in a Wheatstone’s bridge are \(10~\Omega,30~\Omega,30~\Omega\) and \(90~\Omega\) respectively. The emf and internal resistance of the cell are \(7~\text{volt}\) and \(5~\Omega\) respectively. If the galvanometer resistance is \(50~\Omega\) the current drawn from the cell will be:

1. \(0.2~\text{A}\)

2. \(0.1~\text{A}\)

3. \(2.0~\text{A}\)

4. \(1.0~\text{A}\)

2. \(0.1~\text{A}\)

3. \(2.0~\text{A}\)

4. \(1.0~\text{A}\)

Subtopic: Wheatstone Bridge |

76%

From NCERT

AIPMT - 2013

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In the circuit shown cells, \(A\) and \(B\) have negligible resistance. For \(V_A =12 ~\text{V}\), \(R_1 = 500 ~\Omega \), and $\mathrm{}$\(R = 100 ~\Omega \) the galvanometer \((\text{G}) \) shows no deflection. The value of \(V_B\) is:

** **

1. \(4\) V

2. \(2\) V

3. \(12\) V

4. \(6\) V

Subtopic: Kirchoff's Voltage Law |

73%

From NCERT

AIPMT - 2012

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If the voltage across a bulb rated \((220~\text{V}\text-100~\text{W})\) drops by \(2.5\%\) of its rated value, the percentage of the rated value by which the power would decrease is:

1. \(20\%\)

2. \(2.5\%\)

3. \(5\%\)

4. \(10\%\)

Subtopic: Heating Effects of Current |

77%

From NCERT

AIPMT - 2012

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A ring is made of a wire having a resistance of \(R_0=12~\Omega.\). Find points \(\mathrm{A}\) and \(\mathrm{B}\), as shown in the figure, at which a current-carrying conductor should be connected so that the resistance \(R\) of the subcircuit between these points equals \(\frac{8}{3}~\Omega\)$\mathrm{?}$

1. | \(\dfrac{l_1}{l_2} = \dfrac{5}{8}\) | 2. | \(\dfrac{l_1}{l_2} = \dfrac{1}{3}\) |

3. | \(\dfrac{l_1}{l_2} = \dfrac{3}{8}\) | 4. | \(\dfrac{l_1}{l_2} = \dfrac{1}{2}\) |

Subtopic: Combination of Resistors |

51%

From NCERT

AIPMT - 2012

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If power dissipated in the \(9~\Omega\) resistor in the circuit shown is \(36\) W, the potential difference across the \(2~\Omega\) resistor will be:

1. \(8\) V

2. \(10\) V

3. \(2\) V

4. \(4\) V

Subtopic: Heating Effects of Current |

78%

From NCERT

AIPMT - 2011

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A current of \(2~\text{A}\) flows through a \(2~\Omega\) resistor when connected across a battery. The same battery supplies a current of \(0.5~\text{A}\) when connected across a \(9~\Omega\) resistor. The internal resistance of the battery is:

1. | \(\dfrac{1}{3}~\Omega\) | 2. | \(\dfrac{1}{4}~\Omega\) |

3. | \(1~\Omega\) | 4. | \(0.5~\Omega\) |

Subtopic: EMF & Terminal Voltage |

78%

From NCERT

AIPMT - 2011

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The rate of increase of thermo-emf with the temperature at the neutral temperature of a thermocouple:

1. | is zero. |

2. | depends upon the choice of the two materials of the thermocouple. |

3. | is negative. |

4. | is positive. |

Subtopic: Heating Effects of Current |

AIPMT - 2011

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