# The figure given below shows a circuit when resistances in the two arms of the meter bridge are $$5~\Omega$$ and $$R$$, respectively. When the resistance $$R$$ is shunted with equal resistance, the new balance point is at $$1.6l_1$$. The resistance $$R$$ is:              1. $$10~\Omega$$ 2. $$15~\Omega$$ 3. $$20~\Omega$$ 4. $$25~\Omega$$

Subtopic:  Meter Bridge & Potentiometer |
73%
From NCERT
AIPMT - 2014
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A potentiometer circuit has been set up for finding the internal resistance of a given cell. The main battery, used across the potentiometer wire, has an emf of $$2.0~\text{V}$$ and negligible internal resistance. The potentiometer wire itself is $$4~\text{m}$$ long. When the resistance, $$R$$, connected across the given cell, has values of (i) infinity (ii) $$9.5$$, the 'balancing lengths, on the potentiometer wire, are found to be $$3~\text{m}$$ and $$2.85~\text{m}$$, respectively. The value of the internal resistance of the cell is (in ohm):
1. $$0.25$$
2. $$0.95$$
3. $$0.5$$
4. $$0.75$$

Subtopic:  Meter Bridge & Potentiometer |
65%
From NCERT
AIPMT - 2014
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A wire of resistance $$4~\Omega$$ is stretched to twice its original length. The resistance of a stretched wire would be:

 1 $$4~\Omega$$ 2 $$8~\Omega$$ 3 $$16~\Omega$$ 4 $$2~\Omega$$
Subtopic:  Derivation of Ohm's Law |
83%
From NCERT
AIPMT - 2013
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Internal resistance of a $$2.1~\text{V}$$ cell which gives a current of $$0.2~\text{A}$$ through a resistance of $$10~\Omega$$ is:
1. $$0.5~\Omega$$
2. $$0.8~\Omega$$
3. $$1.0~\Omega$$
4. $$0.2~\Omega$$
Subtopic:  EMF & Terminal Voltage |
83%
From NCERT
AIPMT - 2013
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The resistances of the four arms $$P,Q,R~\text{and}~S$$ in a Wheatstone’s bridge are $$10~\Omega,30~\Omega,30~\Omega$$ and $$90~\Omega$$ respectively. The emf and internal resistance of the cell are $$7~\text{volt}$$ and $$5~\Omega$$ respectively. If the galvanometer resistance is $$50~\Omega$$ the current drawn from the cell will be:
1. $$0.2~\text{A}$$
2. $$0.1~\text{A}$$
3. $$2.0~\text{A}$$
4. $$1.0~\text{A}$$

Subtopic:  Wheatstone Bridge |
76%
From NCERT
AIPMT - 2013
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In the circuit shown cells, $$A$$ and $$B$$ have negligible resistance. For $$V_A =12 ~\text{V}$$, $$R_1 = 500 ~\Omega$$, and $\mathrm{}$$$R = 100 ~\Omega$$ the galvanometer $$(\text{G})$$ shows no deflection. The value of $$V_B$$ is:

1. $$4$$ V
2. $$2$$ V
3. $$12$$ V
4. $$6$$ V

Subtopic:  Kirchoff's Voltage Law |
73%
From NCERT
AIPMT - 2012
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If the voltage across a bulb rated $$(220~\text{V}\text-100~\text{W})$$ drops by $$2.5\%$$ of its rated value, the percentage of the rated value by which the power would decrease is:
1. $$20\%$$
2. $$2.5\%$$
3. $$5\%$$
4. $$10\%$$

Subtopic:  Heating Effects of Current |
77%
From NCERT
AIPMT - 2012
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A ring is made of a wire having a resistance of $$R_0=12~\Omega.$$. Find points $$\mathrm{A}$$ and $$\mathrm{B}$$, as shown in the figure, at which a current-carrying conductor should be connected so that the resistance $$R$$ of the subcircuit between these points equals $$\frac{8}{3}~\Omega$$$\mathrm{?}$

 1 $$\dfrac{l_1}{l_2} = \dfrac{5}{8}$$ 2 $$\dfrac{l_1}{l_2} = \dfrac{1}{3}$$ 3 $$\dfrac{l_1}{l_2} = \dfrac{3}{8}$$ 4 $$\dfrac{l_1}{l_2} = \dfrac{1}{2}$$
Subtopic:  Combination of Resistors |
52%
From NCERT
AIPMT - 2012
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If power dissipated in the $$9~\Omega$$ resistor in the circuit shown is $$36$$ W, the potential difference across the $$2~\Omega$$ resistor will be:

1. $$8$$ V
2. $$10$$ V
3. $$2$$ V
4. $$4$$ V

Subtopic:  Heating Effects of Current |
78%
From NCERT
AIPMT - 2011
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A current of $$2~\text{A}$$ flows through a $$2~\Omega$$ resistor when connected across a battery. The same battery supplies a current of $$0.5~\text{A}$$ when connected across a $$9~\Omega$$ resistor. The internal resistance of the battery is:

 1 $$\dfrac{1}{3}~\Omega$$ 2 $$\dfrac{1}{4}~\Omega$$ 3 $$1~\Omega$$ 4 $$0.5~\Omega$$
Subtopic:  EMF & Terminal Voltage |
78%
From NCERT
AIPMT - 2011
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