Given n resistors each of resistance R, what is the ratio of the maximum to minimum resistance?
1. \(\frac{1}{n}\)
2. \(n\)
3. \(\frac{1}{n^2}\)
4. \(n^2\)
Given the resistances of 1Ω, 2Ω, 3Ω, how will we combine them to get an equivalent resistance of (11/3):
1. | 1Ω, 2Ω in parallel and the combination in series with 3Ω |
2. | 3Ω, 2Ω in parallel and the combination in series with 1Ω |
3. | 1Ω, 2Ω and 3Ω in parallel |
4. | 1Ω, 2Ω in series and the combination in parallel with 3Ω |
Three resistors are combined in series. If the combination is connected to a battery of emf 12 V and negligible internal resistance, the potential drop across resistor is:
1. 2 V
2. 5 V
3. 4 V
4. 6 V
Three resistors are combined in parallel. If the combination is connected to a battery of emf 20 V and negligible internal resistance, the total current drawn from the battery is:
1. 10 A
2. 17 A
3. 13 A
4. 19 A
The current drawn from a 12 V supply with internal resistance by the infinite network (shown in the figure) is:
1. 3.12 A
2. 3.72 A
3. 2.29 A
4. 2.37 A