If the gravitational force between two objects were proportional to $$\frac{1}{R}$$ (and not as$$\frac{1}{R^2}$$${}^{}$) where $$R$$ is the separation between them, then a particle in circular orbit under such a force would have its orbital speed $$v$$ proportional to:
1. $$\frac{1}{R^2}$$
2. $$R^{0}$$
3. $$R^{1}$$
4. $$\frac{1}{R}$$

Subtopic: Â Orbital velocity |
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For the moon to cease as the earth's satellite, its orbital velocity has to be increased by a factor of:

 1 $$2$$ 2 $$\sqrt{2}$$ 3 $$1/\sqrt{2}$$ 4 $$4$$
Subtopic: Â Orbital velocity |
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Rohini satellite is at a height of $$500$$ km and Insat-B is at a height of $$3600$$ km from the surface of the earth. The relation between their orbital velocity ($$v_R,~v_i$$) is:
1. $$v_R>v_i$$
2. $$v_R<v_i$$
3. $$v_R=v_i$$
4. no specific relation

Subtopic: Â Orbital velocity |
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AIPMT - 1999
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Two satellites $$A$$ and $$B$$ go around the earth in circular orbits at heights of $$R_A ~\text{and}~R_B$$ respectively from the surface of the earth. Assuming earth to be a uniform sphere of radius $$R_e$$${}_{}$, the ratio of the magnitudes of their orbital velocities is:
1. $$\sqrt{\frac{R_{B}}{R_{A}}}$$
2. $$\frac{R_{B} + R_{e}}{R_{A} + R_{e}}$$
3. $$\sqrt{\frac{R_{B} + R_{e}}{R_{A} + R_{e}}}$$
4. $$\left(\frac{R_{A}}{R_{B}}\right)^{2}$$

Subtopic: Â Orbital velocity |
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The radii of the circular orbits of two satellites $$A$$ and $$B$$ of the earth are $$4R$$ and $$R,$$ respectively. If the speed of satellite $$A$$ is $$3v,$$ then the speed of satellite $$B$$ will be:

 1 $$3v/4$$ 2 $$6v$$ 3 $$12v$$ 4 $$3v/2$$
Subtopic: Â Orbital velocity |
Â 61%
From NCERT
NEET - 2010
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