A rocket is fired vertically upward with a speed of $$\dfrac{v_e}{\sqrt2}$$ from the earth's surface, where $$v_e$$ is escape velocity on the surface of earth. The distance from the surface of earth upto which the rocket can go before returning to the earth is
(Given radius of earth $$=6400~\text{km}$$ ):
 1 $$1600~\text{km}$$ 2 $$3200~\text{km}$$ 3 $$6400~\text{km}$$ 4 $$12800~\text{km}$$
Subtopic: Â Escape velocity |
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From NCERT
NEET - 2024
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The escape velocity for Earth is $$v.$$ A planet having $$9$$ times the mass of Earth and a radius, $$16$$ times that of Earth, has the escape velocity of:
 1 $$\dfrac{v}{3}$$ 2 $$\dfrac{2v}{3}$$ 3 $$\dfrac{3v}{4}$$ 4 $$\dfrac{9v}{4}$$
Subtopic: Â Escape velocity |
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From NCERT
NEET - 2024
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The escape velocity of a body on the earth's surface is $$11.2$$ km/s. If the same body is projected upward with a velocity $$22.4$$ km/s, the velocity of this body at infinite distance from the center of the earth will be:
 1 $$11.2\sqrt2$$ km/s 2 zero 3 $$11.2$$ km/s 4 $$11.2\sqrt3$$ km/s
Subtopic: Â Escape velocity |
From NCERT
NEET - 2023
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The escape velocity from the Earth's surface is $$v$$. The escape velocity from the surface of another planet having a radius, four times that of Earth and the same mass density is:

 1 $$3v$$ 2 $$4v$$ 3 $$v$$ 4 $$2v$$
Subtopic: Â Escape velocity |
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From NCERT
NEET - 2021
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A particle of mass $$m$$ is projected with a velocity, $$v=kV_{e} ~(k<1)$$ from the surface of the earth. The maximum height, above the surface, reached by the particle is: (Where $$V_e=$$ escape velocity, $$R=$$ radius of the earth)

 1 $$\dfrac{R^{2}k}{1+k}$$ 2 $$\dfrac{Rk^{2}}{1-k^{2}}$$ 3 $$R\left ( \dfrac{k}{1-k} \right )^{2}$$ 4 $$R\left ( \dfrac{k}{1+k} \right )^{2}$$
Subtopic: Â Escape velocity |
Â 58%
From NCERT
NEET - 2021
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