A particle is released from a height of $$S$$ above the surface of the earth. At a certain height, its kinetic energy is three times its potential energy. The distance from the earth's surface and the speed of the particle at that instant are respectively:
 1 $${S \over 2},{ \sqrt{3gS} \over 2}$$ 2 $${S \over 4}, \sqrt{3gS \over 2}$$ 3 $${S \over 4},{ {3gS} \over 2}$$ 4 $${S \over 4},{ \sqrt{3gS} \over 3}$$
Subtopic: Â Gravitational Potential Energy |
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From NCERT
NEET - 2021
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The work done to raise a mass $$m$$ from the surface of the earth to a height $$h$$, which is equal to the radius of the earth, is:
1. $$\dfrac{3}{2}mgR$$
2. $$mgR$$
3. $$2mgR$$
4. $$\dfrac{1}{2}mgR$$
Subtopic: Â Gravitational Potential Energy |
Â 65%
From NCERT
NEET - 2019
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Assuming that the gravitational potential energy of an object at infinity is zero, the change in potential energy (final - initial) of an object of mass $$m$$ when taken to a height $$h$$ from the surface of the earth (of radius $$R$$ and mass $$M$$), is given by:

 1 $$-\dfrac{GMm}{R+h}$$ 2 $$\dfrac{GMmh}{R(R+h)}$$ 3 $$mgh$$ 4 $$\dfrac{GMm}{R+h}$$
Subtopic: Â Gravitational Potential Energy |
Â 62%
From NCERT
NEET - 2019
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