The mass of a planet is $$\left ( \dfrac{1}{10} \right )^{\text{th}}$$ that of the earth and its diameter is half that of the earth. The acceleration due to gravity on that planet is:
 1 $$9.8 ~\text{ms}^{-2}$$ 2 $$4.9 ~\text{ms}^{-2}$$ 3 $$3.92 ~\text{ms}^{-2}$$ 4 $$19.6~\text{ms}^{-2}$$
Subtopic: Â Acceleration due to Gravity |
Â 62%
From NCERT
NEET - 2024
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A body weighing $$100~\text{N}$$ on the surface of earth weights $$x~\text{kg-ms}^{-2}$$ at a height $$\dfrac{1}{9} R_E$$ above the surface of earth. The value of $$x$$ ($$g= 10~\text{ms}^{-2}$$ at surface of earth and $$R_E$$ is the radius of earth):
1. $$72$$
2. $$54$$
3. $$81$$
4. $$62$$
Subtopic: Â Acceleration due to Gravity |
Â 77%
From NCERT
NEET - 2024
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An object of mass $$100 ~\text{kg}$$ falls from point $$A$$ to $$B$$ as shown in the figure. The change in its weight, corrected to the nearest integer is ($$R_E$$ is radius of the earth):

1. $$49~\text N$$
2. $$89~\text N$$
3. $$5~\text N$$
4. $$10~\text N$$
Subtopic: Â Acceleration due to Gravity |
Â 56%
From NCERT
NEET - 2024
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If $$R$$ is the radius of the earth and $$g$$ is the acceleration due to gravity on the earth surface. Then the mean density of the earth will be:
 1 $$\dfrac{\pi RG}{12g}$$ 2 $$\dfrac{3\pi R}{4gG}$$ 3 $$\dfrac{3g}{4\pi RG}$$ 4 $$\dfrac{4\pi G}{3gR}$$
Subtopic: Â Acceleration due to Gravity |
Â 76%
From NCERT
NEET - 2023
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Assuming the earth to be a sphere of uniform density, its acceleration due to gravity acting on a body:

 1 increases with increasing altitude. 2 increases with increasing depth. 3 is independent of the mass of the earth. 4 is independent of the mass of the body.
Subtopic: Â Acceleration due to Gravity |
Â 69%
From NCERT
NEET - 2022
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A body weighs $$72~\text{N}$$ on the surface of the earth. What is the gravitational force on it at a height equal to half the radius of the earth?
1. $$32~\text{N}$$
2. $$30~\text{N}$$
3. $$24~\text{N}$$
4. $$48~\text{N}$$

Subtopic: Â Acceleration due to Gravity |
Â 73%
From NCERT
NEET - 2020
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What is the depth at which the value of acceleration due to gravity becomes $$\dfrac{1}{{n}}$$ times it's value at the surface of the earth? (radius of the earth = $$\mathrm{R}$$)
 1 $$\dfrac R {n^2}$$ 2 $$\dfrac {R~(n-1)} n$$ 3 $$\dfrac {Rn} { (n-1)}$$ 4 $$\dfrac R n$$
Subtopic: Â Acceleration due to Gravity |
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From NCERT
NEET - 2020
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A body weighs $$200$$ N on the surface of the earth. How much will it weigh halfway down the centre of the earth?

 1 $$100$$ N 2 $$150$$ N 3 $$200$$ N 4 $$250$$ N
Subtopic: Â Acceleration due to Gravity |
Â 80%
From NCERT
NEET - 2019
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A mass falls from a height $$h$$ and its time of fall $$t$$ is recorded in terms of time period $$T$$ of a simple pendulum. On the surface of the earth, it is found that $$t=2T$$. The entire setup is taken on the surface of another planet whose mass is half of that of the Earth and whose radius is the same. The same experiment is repeated and corresponding times are noted as $$t'$$ and $$T'$$. Then we can say:
1. $$t' = \sqrt{2}T$$
2. $$t'>2T'$$
3. $$t'<2T'$$
4. $$t' = 2T'$$

Subtopic: Â Acceleration due to Gravity |
From NCERT
NEET - 2019
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