A body is moving with a velocity of \(30~\text{m/s}\) towards the east. After \(10~\text s,\) its velocity becomes \(40~\text{m/s}\) towards the north. The average acceleration of the body is:
1. \( 7~\text{m/s}^2\)
2. \( \sqrt{7}~\text{m/s}^2\)
3. \(5~\text{m/s}^2\)
4. \(1~\text{m/s}^2\)

Subtopic:  Acceleration |
 78%
From NCERT
AIPMT - 2011
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A particle is moving in the \(XY\) plane such that \(x = \left(t^2 -2t\right)~\text m,\) and \(y = \left(2t^2-t\right)~\text m,\) then:

1. the acceleration is zero at \(t=1~\text s.\) 
2. the speed is zero at \(t=0~\text s.\)
3. the acceleration is always zero.
4. the speed is \(3~\text{m/s}\) at \(t=1~\text s.\)
Subtopic:  Acceleration |
 73%
From NCERT
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A particle moves so that its position vector is given by \(r=\cos \omega t \hat{x}+\sin \omega t \hat{y}\) where \(\omega\) is a constant. Based on the information given, which of the following is true?

1. The velocity and acceleration, both are parallel to \(r.\)
2. The velocity is perpendicular to \(r\) and acceleration is directed towards the origin.
3. The velocity is not perpendicular to \(r\) and acceleration is directed away from the origin.
4. The velocity and acceleration, both are perpendicular to \(r.\)
Subtopic:  Acceleration |
 71%
From NCERT
NEET - 2016
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A particle is moving along a curve. Select the correct statement.

1. If its speed is constant, then it has no acceleration.
2. If its speed is increasing, then the acceleration of the particle is along its direction of motion.
3. If its speed is decreasing, then the acceleration of the particle is opposite to its direction of motion.
4. If its speed is constant, its acceleration is perpendicular to its velocity.
Subtopic:  Acceleration |
 71%
From NCERT
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