A bullet is fired from a gun at the speed of $$280~\text{ms}^{-1}$$ in the direction $$30^\circ$$ above the horizontal. The maximum height attained by the bullet is: $$\left(g=9.8~\text{m/s}^{2}, \sin30^{\circ}=0.5\right)$$
 1 $$3000~\text{m}$$ 2 $$2800~\text{m}$$ 3 $$2000~\text{m}$$ 4 $$1000~\text{m}$$
Subtopic:  Projectile Motion |
62%
From NCERT
NEET - 2023
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A ball is projected from point $$A$$ with velocity $$20$$ ms–1 at an angle $$60^\circ$$ to the horizontal direction. At the highest point $$B$$ of the path (as shown in figure), the velocity $$v$$ (in ms–1) of the ball will be:

1. $$20$$
2. $$10\sqrt3$$
3. zero
4. $$10$$
Subtopic:  Projectile Motion |
68%
From NCERT
NEET - 2023
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A ball is projected with a velocity of $$10$$ ms–1 at an angle of $$60^\circ$$ with the vertical direction. Its speed at the highest point of its trajectory will be:
1. $$10$$ ms–1
2. zero
3. $$5\sqrt3$$ ms–1
4. $$5$$ ms–1
Subtopic:  Projectile Motion |
59%
From NCERT
NEET - 2022
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A cricket ball is thrown by a player at a speed of $$20$$ m/s in a direction $$30^\circ$$ above the horizontal. The maximum height attained by the ball during its motion is: (Take $$g=10$$ m/s2)
1. $$5$$ m
2. $$10$$ m
3. $$20$$ m
4. $$25$$ m
Subtopic:  Projectile Motion |
73%
From NCERT
NEET - 2022
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A car starts from rest and accelerates at $$5~\text{m/s}^{2}$$. At $$t=4~\text{s}$$, a ball is dropped out of a window by a person sitting in the car. What is the velocity and acceleration of the ball at $$t=6~\text{s}$$? (Take $$g=10~\text{m/s}^2)$$
1. $$20\sqrt{2}~\text{m/s}, 0~\text{m/s}^2$$
2. $$20\sqrt{2}~\text{m/s}, 10~\text{m/s}^2$$
3. $$20~\text{m/s}, 5~\text{m/s}^2$$
4. $$20~\text{m/s}, 0~\text{m/s}^2$$

Subtopic:  Projectile Motion |
61%
From NCERT
NEET - 2021
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A particle moving in a circle of radius $$R$$ with a uniform speed takes a time $$T$$ to complete one revolution. If this particle were projected with the same speed at an angle $$\theta$$ to the horizontal, the maximum height attained by it equals $$4R.$$ The angle of projection, $$\theta$$ is then given by:
 1 $$\theta=\sin ^{-1}\left(\dfrac{\pi^2 {R}}{{gT}^2}\right)^{1/2}$$ 2 $$\theta=\sin ^{-1}\left(\dfrac{2 {gT}^2}{\pi^2 {R}}\right)^{1 / 2}$$ 3 $$\theta=\cos ^{-1}\left(\dfrac{{gT}^2}{\pi^2 {R}}\right)^{1 / 2}$$ 4 $$\theta=\cos ^{-1}\left(\dfrac{\pi^2 {R}}{{gT}^2}\right)^{1 / 2}$$
Subtopic:  Projectile Motion |
69%
From NCERT
NEET - 2021
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A projectile is fired from the surface of the earth with a velocity of $$5$$ ms–1 and at an angle $$\theta$$ with the horizontal. Another projectile fired from another planet with a velocity of $$3$$ ms–1 at the same angle follows a trajectory that is identical to the trajectory of the projectile fired from the Earth. The value of the acceleration due to gravity on the other planet is: (given $$g=9.8$$ ms–2)
1. $$3.5$$ m/s2
2. $$5.9$$ m/s2
3. $$16.3$$ m/s2
4. $$110.8$$ m/s2

Subtopic:  Projectile Motion |
72%
From NCERT
AIPMT - 2014
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The velocity of a projectile at the initial point $$A$$ is $$2\hat i+3\hat j~$$m/s. Its velocity (in m/s) at point $$B$$ is:

 1 $$-2\hat i+3\hat j~$$ 2 $$2\hat i-3\hat j~$$ 3 $$2\hat i+3\hat j~$$ 4 $$-2\hat i-3\hat j~$$
Subtopic:  Projectile Motion |
83%
From NCERT
AIPMT - 2013
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The horizontal range and the maximum height of a projectile are equal. The angle of projection of the projectile is:
1. $$\theta = \tan^{-1}\left(\frac{1}{4}\right)$$
2. $$\theta = \tan^{-1}(4)$$
3. $$\theta = \tan^{-1}(2)$$
4. $$\theta = 45^{\circ}$$
Subtopic:  Projectile Motion |
75%
From NCERT
AIPMT - 2012
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A missile is fired for a maximum range with an initial velocity of $$20$$ m/s. If $$g=10$$ m/s2, then the range of the missile will be:

 1 $$50$$ m 2 $$60$$ m 3 $$20$$ m 4 $$40$$ m
Subtopic:  Projectile Motion |
83%
From NCERT
AIPMT - 2011
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