The unit of length, parsec is used for the measurement of:

 1 wavelength of light 2 size of an atom 3 astronomical distance 4 height of a building
Subtopic: Â Measurement & Measuring Devices |
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The angle of $$1'$$ (minute of an arc) in radian is nearly equal to:
1. $$2.91 \times 10^{-4} ~\mathrm{rad}$$
2. $$4.85 \times 10^{-4} ~\mathrm{rad}$$
3. $$4.80 \times 10^{-6} ~\mathrm{rad}$$
4. $$1.75 \times 10^{-2} ~\mathrm{rad}$$

Subtopic: Â Measurement & Measuring Devices |
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From NCERT
NEET - 2020
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The angle of $$1^\circ$$ (degree) will be equal to:
(Use $$360^\circ=2\pi$$ rad
)
1. $$1.034\times10^{-3}$$ rad
2. $$1.745\times10^{-2}$$ rad
3. $$1.524\times10^{-2}$$ rad
4. $$1.745\times10^{3}$$ rad

Subtopic: Â Measurement & Measuring Devices |
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A screw gauge has the least count of $$0.01~\text{mm}$$ and there are $$50$$ divisions in its circular scale. The pitch of the screw gauge is:

 1 $$0.25$$ mm 2 $$0.5$$ mm 3 $$1.0$$ mm 4 $$0.01$$ mm
Subtopic: Â Measurement & Measuring Devices |
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From NCERT
NEET - 2020
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Consider a screw gauge without any zero error. What will be the final reading corresponding to the final state as shown?
It is given that the circular head translates $$P$$ MSD in $${N}$$ rotations. ($$1$$ MSD $$=$$ $$1~\text{mm}$$.)

1. $$\left(\frac{{P}}{{N}}\right)\left(2+\frac{45}{100}\right) \text{mm}$$
2. $$\left(\frac{{N}}{{P}}\right)\left(2+\frac{45}{{N}}\right) \text{mm}$$
3. $$P\left(\frac{2}{{N}}+\frac{45}{100}\right) \text{mm}$$
4. $$\left(2+\frac{45}{100} \times \frac{{P}}{{N}}\right) \text{mm}$$

Subtopic: Â Measurement & Measuring Devices |
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In an experiment, the height of an object measured by a vernier callipers having least count of $$0.01~\text{cm}$$ is found to be $$5.72~\text{cm}$$. When no object is there between jaws of this vernier callipers, the reading of the main scale is $$0.1$$ cm and the reading of the vernier scale is $$0.3~\text{mm}$$. The correct height of the object is:
1. $$5.72 ~\text{cm}$$
2. $$5.59~\text{cm}$$
3. $$5.85~\text{cm}$$
4. $$5.69~\text{cm}$$

Subtopic: Â Measurement & Measuring Devices |
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The main scale of a vernier calliper has $$n$$ divisions/cm. $$n$$ divisions of the vernier scale coincide with $$(n-1)$$ divisions of the main scale. The least count of the vernier calliper is:
1. $$\dfrac{1}{(n+1)(n-1)}$$ cm
2. $$\dfrac{1}{n}$$ cm
3. $$\dfrac{1}{n^{2}}$$ cm
4. $$\dfrac{1}{(n)(n+1)}$$ cm

Subtopic: Â Measurement & Measuring Devices |
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From NCERT
NEET - 2019
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