The dimensional formula for impulse is:
1. | \([MLT^{-2}]\) | 2. | \([MLT^{-1}]\) |
3. | \([ML^2T^{-1}]\) | 4. | \([M^2LT^{-1}]\) |
In the relation, \(y=a \cos (\omega t-k x)\), the dimensional formula for \(k\) will be:
1. \( {\left[M^0 L^{-1} T^{-1}\right]} \)
2. \({\left[M^0 L T^{-1}\right]} \)
3. \( {\left[M^0 L^{-1} T^0\right]} \)
4. \({\left[M^0 L T\right]}\)
The percentage errors in the measurement of mass and speed are \(2\%\) and \(3\%\) respectively. How much will be the maximum error in the estimation of the kinetic energy obtained by measuring mass and speed:
1. | \(11\%\) | 2. | \(8\%\) |
3. | \(5\%\) | 4. | \(1\%\) |
The decimal equivalent of \(\frac{1}{20} \) up to three significant figures is:
1. | \(0.0500\) | 2. | \(0.05000\) |
3. | \(0.0050\) | 4. | \(5.0 \times 10^{-2}\) |
The periods of oscillation of a simple pendulum in an experiment are recorded as 2.63 s, 2.56 s, 2.42 s, 2.71 s, and 2.80 s respectively. The average absolute error will be:
1. 0.1 s
2. 0.11 s
3. 0.01 s
4. 1.0 s
The length of a cylinder is measured with a meter rod having the least count of \(0.1~\text{cm}\). Its diameter is measured with vernier callipers having the least count of \(0.01~\text{cm}\). Given that the length is \(5.0~\text{cm}\) and the radius is \(2.0~\text{cm}\). The percentage error in the calculated value of the volume will be:
1. | \(1\%\) | 2. | \(2\%\) |
3. | \(3\%\) | 4. | \(4\%\) |
A physical quantity \(P\) is given by \(P=\dfrac{A^3 B^{1/2}}{C^{-4}D^{3/2}}.\) The quantity which contributes the maximum percentage error in \(P\) is:
1. | \(A\) | 2. | \(B\) |
3. | \(C\) | 4. | \(D\) |
The number of significant figures in the numbers \(25.12,\) \(2009,\) \(4.156\) and \(1.217\times 10^{-4}\) is:
1. | \(1\) | 2. | \(2\) |
3. | \(3\) | 4. | \(4\) |
A physical quantity \(A\) is related to four observable quantities \(a\), \(b\), \(c\) and \(d\) as follows, \(A= \frac{a^2b^3}{c\sqrt{d}},\) the percentage errors of measurement in \(a\), \(b\), \(c\) and \(d\) are \(1\%\), \(3\%\), \(2\%\) and \(2\%\) respectively. The percentage error in quantity \(A\) will be:
1. \(12\%\)
2. \(7\%\)
3. \(5\%\)
4. \(14\%\)
If \(97.52\) is divided by \(2.54\), the correct result in terms of significant figures is:
1. | \( 38.4 \) | 2. | \(38.3937 \) |
3. | \( 38.394 \) | 4. | \(38.39\) |