Two clocks are being tested against a standard clock located in a national laboratory. At 12:00:00 noon by the standard clock, the readings of the two clocks are:

 Days Clock 1 Clock 2 Monday 12:00:05 10:15:06 Tuesday 12:01:15 10:14:59 Wednesday 11:59:08 10:15:18 Thursday 12:01:50 10:15:07 Friday 11:59:15 10:14:53 Saturday 12:01:30 10:15:24 Sunday 12:01:19 10:15:11

If you are doing an experiment that requires precision time interval measurements, which of the two clocks will you prefer?

 1 clock 1 2 clock 2 3 neither clock 1 nor clock 2 4 both clock 1 and clock 2

Subtopic:  Errors |
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The temperatures of two bodies measured by a thermometer are $$t_1=20^\circ \text{C}\pm0.5^\circ \text{C}$$ and $$t_2=50^\circ \text{C}\pm0.5^\circ \text{C}.$$ The temperature difference with permissible error is:
1. $$31^\circ \text{C}\pm0.5^\circ \text{C}$$
2. $$30^\circ \text{C}\pm1.0^\circ \text{C}$$
3. $$30^\circ \text{C}\pm0.0^\circ \text{C}$$
4.
$$30^\circ \text{C}\pm1.5^\circ \text{C}$$

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The resistance $$R=\frac{V}{I}$$ where $$V=(100 \pm 5) ~V$$ and $$I=(10 \pm 0.2)~ A$$. The percentage error in $$R$$ is:
1. $$5\%$$
2. $$2\%$$
3. $$7\%$$
4.
$$3\%$$

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Two resistors of resistances  ohm and  ohm are connected in series, the equivalent resistance of the series combination is:

1.  (300 ± 7) ohm

2.  (300 ± 1) ohm

3.  (300 ± 0) ohm

4.  (100 ± 1) ohm

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Two resistors of resistances  ohm and  ohm are connected in parallel. The equivalent resistance of the parallel combination is:

1.  (300 ± 7) ohm

2.  (66.7 ± 7) ohm

3.  (66.7 ± 1.8) ohm

4.  (100 ± 1) ohm

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The relative error in $$Z,$$ if $$Z=\frac{A^{4}B^{1/3}}{CD^{3/2}}$$ is:
1. $$\frac{\Delta A}{A}+\frac{\Delta B}{B}+\frac{\Delta C}{C}+\frac{\Delta D}{D}$$

2. $$4\frac{\Delta A}{A}+\frac{1}{3}\frac{\Delta B}{B}-\frac{\Delta C}{C}- \frac{3}{2}\frac{\Delta D}{D}$$

3. $$4\frac{\Delta A}{A}+\frac{1}{3}\frac{\Delta B}{B}+\frac{\Delta C}{C}+\frac{2}{3}\frac{\Delta D}{D}$$

4. $$4\frac{\Delta A}{A}+\frac{1}{3}\frac{\Delta B}{B}+\frac{\Delta C}{C}+\frac{3}{2}\frac{\Delta D}{D}$$

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The period of oscillation of a simple pendulum is . Measured value of L is 20.0 cm known to 1 mm accuracy and time for 100 oscillations of the pendulum is found to be 90 s using a wrist watch of 1 s resolution. The percentage error in is:

1.  $2%$

2.  $3%$

3.  $5%$

4.  $0%$

Subtopic:  Errors |
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