In order to find out the different types of gametes produced by a pea plant having the genotype AaBb, it should be crossed to a plant with the genotype:
| 1. | AaBb | 2. | aabb |
| 3. | AABB | 4. | aaBB |
Which of the following is not a hereditary disease:
| 1. | Haemophilia | 2. | Cretinism |
| 3. | Cystic fibrosis | 4. | Thalasasemia |
Haemophilia is more commonly seen in human males than in human females because:
| 1. | This disease is due to a Y-linked recessive mutation |
| 2. | This disease is due to an X-linked recessive mutation |
| 3. | This disease is due to an X-linked dominant mutation |
| 4. | A greater proportion of girls die in infancy |
A woman with 47 chromosomes, due to three copies of chromosome 21, is characterized by:
| 1. | Turner syndrome | 2. | Down syndrome |
| 3. | Superfemaleness | 4. | Triploidy |
A man and a woman, who do not show any apparent signs of a certain inherited disease, have seven children (2 daughters and 5 sons). Three of the sons suffer from the given disease but none of the daughters are affected. Which of the following mode of inheritance might be the reason for this disease?
| 1. | Sex-limited recessive | 2. | Autosomal dominant |
| 3. | Sex-linked recessive | 4. | Sex-linked dominant |
If a female having gene for haemophilia and colour-blindness on one X-chromosome marries a normal male, then what are the chances in their offspring?
1. 50% sons diseased and 50% normal
2. All normal offspring
3. 100% daughters are carrier
4. 100% sons diseased
Reason for trisomy in Down's syndrome is:
1. Non-disjunction during sperm formation
2. Non-disjunction during egg formation
3. Non-disjunction at the time of egg or sperm formation
4. Addition of one extra chromosome during mitosis
Mental retardation in man occurs due to:
1. Loss of one X chromosome
2. Addition of one X chromosome
3. Slight growth in Y
4. Overgrowth in Y
ABO blood group has:
1. Two codominant and one recessive allele
2. Two codominant and two recessive allele
3. Two incompletely dominant genes
4. Two pseudo alleles
A normal woman, whose father was colour-blind is married to a normal man. The sons would be:
1. 50% colour-blind
2. All normal
3. All colour-blind
4. 75 % colour-blind