The energy equivalent of one atomic mass unit is:
1. \(1.6\times 10^{-19}~\text{J}\)
2. \(6.02\times 10^{23}~\text{J}\)
3. \(931~\text{MeV}\)
4. \(9.31~\text{MeV}\)

Subtopic:  Mass-Energy Equivalent |
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A nuclear reaction along with the masses of the particle taking part in it is as follows;
  \(~~A ~~~~+~~~ B~~~~~ \rightarrow~~~~C ~~+~~~~ D~~~~~ ~~Q~ MeV\\ \small{1.002~~~~~~~~ 1.004 ~~~~~~~~~~~~~1.001~~~~~~~1.003}\\ \small{amu~~~~~~~~~~amu~~~~~~~~~~~~~~amu~~~~~~~~~amu} ~~\)
The energy \(Q\) liberated in the reaction is:
1. \(1.234\) MeV
2. \(0.931\) MeV
3. \(0.465\) MeV
4. \(1.862\) MeV

Subtopic:  Mass-Energy Equivalent |
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Determine the energy released in the process:
\({}_{1}^{2}\mathrm{H}+ {}_{1}^{2}\mathrm{H}\rightarrow {}_{2}^{4}\mathrm{He}+Q\)
Given: \(M\left({}_{1}^{2}\mathrm{H}\right)= 2.01471~\text{amu}, M\left({}_{2}^{4}\mathrm{He}\right)= 4.00388~\text{amu}\)
1. \(3.79\) MeV
2. \(13.79\) MeV
3. \(0.79\) MeV 
4. \(23.79\) MeV
Subtopic:  Mass-Energy Equivalent |
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The energy required in \(\text{MeV/c}^2 \) to separate \({ }_8^{16} \mathrm{O}\) into its constituents is:
(Given: mass defect for \({ }_8^{16} \mathrm{O}=0.13691~ \text{amu}\))
1. \(127.5\)
2. \(120.0\)
3. \(222.0\)
4. \(119.0\)

Subtopic:  Mass-Energy Equivalent |
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If an electron and a positron annihilate, then the energy released is:
1. \(3.2\times 10^{-13}~\text{J}\)
2. \(1.6\times 10^{-13}~\text{J}\)
3. \(4.8\times 10^{-13}~\text{J}\)
4. \(6.4\times 10^{-13}~\text{J}\)

Subtopic:  Mass-Energy Equivalent |
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The energy equivalent of \(0.5\) g of a substance is:
1. \(4.5\times10^{13}\) J
2. \(1.5\times10^{13}\) J
3. \(0.5\times10^{13}\) J
4. \(4.5\times10^{16}\) J

Subtopic:  Mass-Energy Equivalent |
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From NCERT
NEET - 2020
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If a proton and anti-proton come close to each other and annihilate, how much energy will be released?

1. \(1.5 \times10^{-10}~\text{J}\) 2. \(3 \times10^{-10}~\text{J}\)
3. \(4.5 \times10^{-10}~\text{J}\) 4. None of these
Subtopic:  Mass-Energy Equivalent |
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Calculate the \(Q\text-\)value of the nuclear reaction:
\(2~{ }_{6}^{12} \mathrm{C}\rightarrow{ }_{10}^{20} \mathrm{Ne}+{ }_2^4 \mathrm{He}\)
The following data are given:
\(m({ }_{6}^{12} \mathrm{C})=12.000000~\text{amu}\)
\(m({ }_{10}^{20} \mathrm{Ne})=19.992439~\text{amu}\)
\(m({ }_{2}^{4} \mathrm{He})=4.002603~\text{amu}\)
1. \(3.16~\text{MeV}\)
2. \(5.25~\text{MeV}\)
3. \(3.91~\text{MeV}\)
4. \(4.65~\text{MeV}\)

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A certain mass of Hydrogen is changed to Helium by the process of fusion. The mass defect in the fusion reaction is \(0.02866\) u. The energy liberated per nucleon is: (Given \(1\) u = \(931\) MeV)
1. \(26.7\) MeV 2. \(6.675\) MeV
3. \(13.35\) MeV 4. \(2.67\) MeV
Subtopic:  Mass-Energy Equivalent |
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AIPMT - 2013
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The rest energy of an electron is:
1. \(510\) KeV 2. \(931\) KeV
3. \(510\) MeV 4. \(931\) MeV
Subtopic:  Mass-Energy Equivalent |
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