Q. No.A nucleus represented by the symbol \({}_{Z}^{A}\mathrm{X}\) has:
| 1. | \(Z\) protons and \(A-Z\) neutrons |
| 2. | \(Z\) protons and \(A\) neutrons |
| 3. | \(A\) protons and \(Z-A\) neutrons |
| 4. | \(Z\) neutrons and \(A-Z\) protons |
Subtopic: Nuclear Binding Energy |
90%
From NCERT
AIPMT - 2004
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Which of the following pairs of nuclei are isotones?
1. \({}_{34}^{74}\mathrm{Se}, {}_{31}^{71}\mathrm{Ca}\)
2. \({}_{42}^{92}\mathrm{Mo}, {}_{40}^{92}\mathrm{Zr}\)
3. \({}_{38}^{81}\mathrm{Sr}, {}_{38}^{86}\mathrm{Sr}\)
4. \({}_{20}^{40}\mathrm{Ca}, {}_{16}^{32}\mathrm{S}\)
1. \({}_{34}^{74}\mathrm{Se}, {}_{31}^{71}\mathrm{Ca}\)
2. \({}_{42}^{92}\mathrm{Mo}, {}_{40}^{92}\mathrm{Zr}\)
3. \({}_{38}^{81}\mathrm{Sr}, {}_{38}^{86}\mathrm{Sr}\)
4. \({}_{20}^{40}\mathrm{Ca}, {}_{16}^{32}\mathrm{S}\)
Subtopic: Nuclear Binding Energy |
85%
From NCERT
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The binding energy of deuteron is \(2.2\) MeV and that of \({}_{2}^{4}\mathrm{He}\) is \(28\) MeV. If two deuterons are fused to form one \({}_{2}^{4}\mathrm{He}\) then the energy released is:
| 1. | \(25.8\) MeV | 2. | \(23.6\) MeV |
| 3. | \(19.2\) MeV | 4. | \(30.2\) MeV |
Subtopic: Nuclear Binding Energy |
82%
From NCERT
AIPMT - 2006
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How does the binding energy per nucleon vary with the increase in the number of nucleons?
| 1. | decrease continuously with mass number. |
| 2. | first decreases and then increases with an increase in mass number. |
| 3. | first increases and then decreases with an increase in mass number. |
| 4. | increases continuously with mass number. |
Subtopic: Nuclear Binding Energy |
80%
From NCERT
NEET - 2013
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If in a nuclear fusion process. the masses of the fusing nuclei be \(m_1\) and \(m_2\) and the mass of the resultant nucleus be \(m_3,\) then:
| 1. | \( m_3=\left|m_1-m_2 \right|\) | 2. | \( m_3<\left ( m_1+m_2 \right ) \) |
| 3. | \( m_3>\left ( m_1+m_2 \right ) \) | 4. | \( m_3=\left ( m_1+m_2 \right ) \) |
Subtopic: Nuclear Binding Energy |
78%
From NCERT
AIPMT - 2004
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The binding energy per nucleon of deuterium and helium atom is \(1.1\) MeV and \(7.0\) MeV. If two deuterium nuclei fuse to form a helium atom, the energy released is:
1. \(19.2\) MeV
2. \(23.6\) MeV
3. \(26.9\) MeV
4. \(13.9\) MeV
1. \(19.2\) MeV
2. \(23.6\) MeV
3. \(26.9\) MeV
4. \(13.9\) MeV
Subtopic: Nuclear Binding Energy |
76%
From NCERT
PMT - 2001
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In a fission reaction,
\(^{236}_{92}\mathrm{U}\rightarrow ~^{117}\mathrm{X}~+~^{117}\mathrm{Y}~+~^1_0n~+~^1_0n,\) the binding energy per nucleon of \(\mathrm{X}\) and \(\mathrm{Y}\) is \(8.5\) MeV whereas that of \(^{236}\mathrm{U}\) is \(7.6\) MeV. The total energy liberated will be about:
1. \(2000\) MeV
2. \(200\) MeV
3. \(2\) MeV
4. \(1\) keV
\(^{236}_{92}\mathrm{U}\rightarrow ~^{117}\mathrm{X}~+~^{117}\mathrm{Y}~+~^1_0n~+~^1_0n,\) the binding energy per nucleon of \(\mathrm{X}\) and \(\mathrm{Y}\) is \(8.5\) MeV whereas that of \(^{236}\mathrm{U}\) is \(7.6\) MeV. The total energy liberated will be about:
1. \(2000\) MeV
2. \(200\) MeV
3. \(2\) MeV
4. \(1\) keV
Subtopic: Nuclear Binding Energy |
76%
From NCERT
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The mass of a proton is \(1.0073\) u and that of a neutron is \(1.0087\) u (u = atomic mass unit). The binding energy of \({}_{2}^{4}\mathrm{He}\) is: (Given: helium nucleus mass ≈ \(4.0015\) u)
| 1. | \(0.0305\) J | 2. | \(0.0305\) erg |
| 3. | \(28.4\) MeV | 4. | \(0.061\) u |
Subtopic: Nuclear Binding Energy |
75%
From NCERT
AIPMT - 2003
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If \(M(A,Z)\), \(M_p\) and \(M_n\) denote the masses of the nucleus \({}_{Z}^{A}\mathrm{X}\), proton, and neutron respectively in units of u (\(1\) u = \(931.5\) MeV/c2) and \(BE\) represents its binding energy in MeV, then:
| 1. | \(M(A, Z)=Z_p+(A-Z) M_n-B E / c^2\) |
| 2. | \({M}({A}, {Z})={ZM}_{p}+({A}-{Z}) {M}_{n}+{BE}\) |
| 3. | \(M(A, Z)=Z_p+(A-Z) M_n-B E\) |
| 4. | \({M}({A}, {Z})={ZM}_{p}+({A}-{Z}) {M}_{n}+{BE/c}^2 \) |
Subtopic: Nuclear Binding Energy |
65%
From NCERT
AIPMT - 2008
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In the reaction \({}_{1}^{2}\mathrm{H}+ {}_{1}^{3}\mathrm{H}\rightarrow {}_{2}^{4}\mathrm{He}+ {}_{0}^{1}\mathrm{n}\)
if the binding energies of \({}_{1}^{2}\mathrm{H}, {}_{1}^{3}\mathrm{H},\) and \({}_{2}^{4}\mathrm{He}\) are respectively \(a,b,\) and \(c\) (in MeV), then the energy in (MeV) released in this reaction is:
1. \(c+a-b\)
2. \(c-a-b\)
3. \(a+b+c\)
4. \(a+b-c\)
if the binding energies of \({}_{1}^{2}\mathrm{H}, {}_{1}^{3}\mathrm{H},\) and \({}_{2}^{4}\mathrm{He}\) are respectively \(a,b,\) and \(c\) (in MeV), then the energy in (MeV) released in this reaction is:
1. \(c+a-b\)
2. \(c-a-b\)
3. \(a+b+c\)
4. \(a+b-c\)
Subtopic: Nuclear Binding Energy |
73%
From NCERT
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