If the K.E of an electron and a photon is the same, then the relation between their de-Broglie wavelength will be:
1. \(\lambda_{ph}< \lambda_e\)
2. \(\lambda_{ph}= \lambda_e\)
3. \(\lambda_{ph}>\lambda_e\)
4. \(\lambda_{ph}= 2\lambda_e\)
Add Note
Subtopic: Â De-broglie Wavelength |
 54%
From NCERT
AIPMT - 1999
Other Reason
Highlight in NCERT
To view explanation, please take trial in the course.
NEET 2025 - Target Batch
Hints
Links
To view explanation, please take trial in the course.
NEET 2025 - Target Batch
Upgrade Your Plan
Upgrade now and unlock your full question bank experience with daily practice.
If particles are moving with the same velocity, then the de-Broglie wavelength is maximum for:
1. proton
2. \(\alpha\text-\)particle
3. neutron
4. \(\beta\text-\)particle
Add Note
Subtopic: Â De-broglie Wavelength |
 64%
From NCERT
AIPMT - 2002
Other Reason
Highlight in NCERT
To view explanation, please take trial in the course.
NEET 2025 - Target Batch
Hints
To view explanation, please take trial in the course.
NEET 2025 - Target Batch
Upgrade Your Plan
Upgrade now and unlock your full question bank experience with daily practice.