Three resistances \(\mathrm P\), \(\mathrm Q\), and \(\mathrm R\), each of \(2~\Omega\) and an unknown resistance \(\mathrm{S}\) form the four arms of a Wheatstone bridge circuit. When the resistance of \(6~\Omega\) is connected in parallel to \(\mathrm{S}\), the bridge gets balanced. What is the value of \(\mathrm{S}\)?
1. \(2~\Omega\)
2. \(3~\Omega\)
3. \(6~\Omega\)
4. \(1~\Omega\)

For the network shown in the figure below, the value of the current i is:

1. $\frac{18\mathrm{V}}{5}$

2. $\frac{5\mathrm{V}}{9}$

3. $\frac{9\mathrm{V}}{35}$

4. $\frac{5\mathrm{V}}{18}$

Five equal resistances each of resistance R are connected as shown in the figure below. A battery of V volts is connected between A and B. The current flowing in AFCEB will be:

1. V/R

2. V/2R

3. 2V/R

4. 3V/R

In a Wheatstone bridge, all four arms have equal resistance \(R.\) If the resistance of the galvanometer arm is also \(R,\) the equivalent resistance of the combination is:

The resistance of each arm of the wheat stone bridge is \(10~ \Omega.\) A resistance of \(10~ \Omega\) is connected in series with a galvanometer. The equivalent resistance across the battery will be:
1.\(10~ \Omega\)
2.\(15~ \Omega\)
3. \(20~ \Omega\)
4. \(40~ \Omega\)

The net resistance of the circuit between \(A\) and \(B\) is: